Find min and max value of vector without using built-in function

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Dan Kristen
Dan Kristen 2022-9-19
评论： Dan Kristen 2022-9-19
Hello, I know that this question has been already asked many times, however, I kind of struggle to execute it. Max shows correct result, but the not the minimum value. What could be the solution?
A = [9 6 8 3 6 8 2 1 3 9 1 0 2]
maxval = A(1);
minval = 1;
for i = 1:length(A)
if A(i) > maxval
maxval = A(i);
else A(i) < minval
minval = A(i)
end
end

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采纳的回答

dpb
dpb 2022-9-19
编辑：dpb 2022-9-19
...
minval=maxval;
...
if ...
...
elseif A(i) < minval %%% HERE'S YOUR PROBLEM...SEE IT???
...
You missed the "if" part on the "else" clause -- so every thing that wasn't greater than went there and the {A(i) < minval) clause did nothing except display the result of the test to the command line; had no bearing on the logic.
  4 个评论
显示 2更早的评论
Voss
Voss 2022-9-19
Ran in:
The if/elseif should really be two independent ifs if initializing with Infs:
A = 1:10; % strictly increasing -> elseif condition never checked
maxval = -Inf;
minval = Inf;
for i = 1:length(A)
if A(i) > maxval
maxval = A(i);
elseif A(i) < minval
minval = A(i);
end
end
minval,maxval % minval remains Inf
minval = Inf
maxval = 10
A = 1:10;
maxval = -Inf;
minval = Inf;
for i = 1:length(A)
if A(i) > maxval
maxval = A(i);
end
if A(i) < minval
minval = A(i);
end
end
minval,maxval
minval = 1
maxval = 10

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更多回答（1 个）

Matt J
Matt J 2022-9-19
%maxval = A(1);
%minval = 1;
maxval = -inf;
minval = +inf;

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