Compiled standalone matlab executable fails at math; what am I doing wrong?

Question

Tino de Bruijn 2015-3-1

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/180970-compiled-standalone-matlab-executable-fails-at-math-what-am-i-doing-wrong

回答： Tino de Bruijn 2015-3-2

Given file test.m:

function test( a, b )
%UNTITLED Summary of this function goes here
%   Detailed explanation goes here
a
b
x = a + b;
x
fileID = fopen('test.out', 'w');
fprintf(fileID, 'x=%d', x);
fprintf('%s', 'test.out');
end

compiled with: mcc -m -R nodisplay test.m -d out/

I would expect: out/test.app/Contents/MacOS/test 1 1

To give me 2, both in test.out and on the console. It however returns:

a =
1
b =
1
x =
      98
test.out

And test.out contains: x=98

I am flabbergasted... Within matlab everything works as expected. What changes during compile? And how do I fix this

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Answer 1

Andrew Schenk 2015-3-1

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/180970-compiled-standalone-matlab-executable-fails-at-math-what-am-i-doing-wrong#answer_169768

在 MATLAB Online 中打开

When you use the MATLAB Compiler, the input argument type will strings.

Loren talks a little more about this here http://blogs.mathworks.com/loren/2010/12/21/strings-and-numbers-as-arguments/

When the function displays a and b, it displays the string. However when the addition is preformed, MATLAB dynamically converts the strings into numbers, but using their ASCII value. The character 1 has an ASCII value of 49. Thus 49+49 = 98.

What you should do instead is add the following to the top of your function: