how to delete the rest of the zeros from a matrix

suppose this the output c=[0 0 0 0; 0 0 0 0; 1 1 1 1] now how could i delete the other zeros for a looop and only print the last row??

1 个评论

Is that as complex as the problem gets or do you have case where some 1s appear in a row with 0s? If so are you expecting the output to simply be a 1d array of basically however many 1s exist in c, irrespective of the structure of where they appear?

请先登录,再进行评论。

 采纳的回答

To remove 0, you can simply do: c(~c) = []; you don't need a loop! Beauty of matlab :)
~c is essentially looking for empty values in c. In Matlab, 0 means empty value and you can simply remove it by replacing it with []
>> c=[0 0 0 0; 0 0 0 0; 1 1 1 1]
c =
0 0 0 0
0 0 0 0
1 1 1 1
>> c(~c) = []
c =
1 1 1 1
>>

2 个评论

when i m doing this all columns are not showing i have 41 columns and 10 rows but i dont know why this happening here only shows 13 or 14 columns??? but why??
I need to know what exactly it is that you're doing. Post your code here in the comments so I can answer why you're getting unexpected number of columns.

请先登录,再进行评论。

更多回答(0 个)

类别

帮助中心File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by