use f=@(x) as an argument of a function.m

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I have the function
function [ k ] = New_Raph( f,df,x,tol)
x_old =x;
x=1000;
while abs(x_old-x) > tol
x_old = x;
delta=-f(x)/df(x);
x= x-delta;
end
k=x;
end
And i want to calculate in a new .m file:
f=@(x) x.^5-0.4475.*x.^4-3.1.*x.^3+3.085.*x.^2-0.962.*x+0.0943;
df1=@(x) 5.*x.^4-1.79.*x.^3-9.3.*x^2+6.17.*x-0.962;
New_Raph(@f1,@df1,0,0.1)
What is wrong?

采纳的回答

per isakson
per isakson 2015-3-13
编辑:per isakson 2015-3-13
Replace
New_Raph(@f1,@df1,0,0.1)
by
New_Raph(f,df1,0,0.1)
f or f1 - a typo?
&nbsp
Addendum triggered by &nbsp It did not work
Try this example
>> my_sin = @(x) sin(x)
my_sin =
@(x)sin(x)
>> arrayfun( my_sin, pi/6*[1,2,3] )
ans =
0.5000 0.8660 1.0000
>> arrayfun( @sin, pi/6*[1,2,3] )
ans =
0.5000 0.8660 1.0000
and
>> arrayfun( @my_sin, pi/6*[1,2,3] )
Error: "my_sin" was previously used as a variable, conflicting with its use
here as the name of a function or command.
  2 个评论
DDD
DDD 2015-3-13
编辑:DDD 2015-3-13
It did not work. I tryed making f1.m and df1.m and it solved but in this way it is much cleaner.
Stephen23
Stephen23 2015-3-13
"It did not work" does not tell us what happened when you tried it: was there an error message, unexpected values or something else?
It should work, according to the information that you have given us. Can you show us your exact code?

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更多回答(1 个)

Matt J
Matt J 2015-3-13

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