How to plot a math function with a vector

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David Sicic
David Sicic 2022-10-19
评论： David Sicic 2022-10-19
Hello everbody,
I have a problem with a task. I've read an excel data into matlab and worked with this data. As i made an integral with the values of my excel data, i now have to take those values and make a math function as following : Zth = (Tmax - T_j) / P. I dont know how to implimate that vector of T_j into the function and generate a plot out of it.
Best regards
David
clear all;
close all;
clc;
values = xlsread('Beispiel-Kurven', 'Fit 0');
cooling_time = values(:,1)';
R_F = values(:,4);
R_F = R_F(~isnan(R_F))';
C_F = values(:,5);
C_F = C_F(~isnan(C_F))';
dZ_th = @(t) 0;
for v = 1:length(R_F)
dZ_th = @(t) dZ_th(t) + exp(-t / (R_F(v) * C_F(v))) / C_F(v);
end
P = @(t) 10;
T_j_scalar_t = @(t) integral(@(tau) P(tau) * dZ_th(t - tau), 0, t);
T_j = @(t) arrayfun(T_j_scalar_t, t);
Tmax = values(1,2)
Zth = (Tmax - T_j_scalar_t) / P
semilogx(cooling_time, Zth(cooling_time))
%semilogx(cooling_time, T_j(cooling_time))
  2 个评论
Torsten
Torsten 2022-10-19
Is it really correct that you want dZ_th to be defined as
dZ_th(t) = sum_{v=1}^{v=N} exp( -t*( R_F(v) * C_F(v) ) ) / C_F(v);
where N = length(R_F) ?

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采纳的回答

Torsten
Torsten 2022-10-19
编辑：Torsten 2022-10-19
Then maybe
T_j_scalar_t = @(t) integral(@(tau) P(tau) .* dZ_th(t - tau), 0, t);
T_j = arrayfun(@(t)T_j_scalar_t(t), cooling_time);
Tmax = values(1,2);
Zth = (Tmax - T_j) ./ P(cooling_time);
semilogx(cooling_time, Zth)
  4 个评论
显示 2更早的评论
Torsten
Torsten 2022-10-19
编辑：Torsten 2022-10-19
T_j and P(cooling_time) are vectors with the length of the array "cooling_time".
You want to divide them elementwise, thus ./ instead of /
Since P is a constant function, you could alternatively have used
Zth = (Tmax - T_j) / P(cooling_time(1));
David Sicic
David Sicic 2022-10-19
Great, thank you for your time and explanation!

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