Finding the most common element in the first row of a matrix

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Hi there
I have a matrix A, and I am wanting to take the first non zero element of each column. For example, for
A =[
1 2 0 1,
4 1 2 2,
2 3 4 3,
3 4 1 4
]
I want to have
1 2 2 3
and then find the most common element.
I looked at previous answers, and used the following code
c=arrayfun(@(x)find(A(:,x),1,'first'),1:size(A,2));
The above code works, but when I use it in a loop of size more than 10 it does not work anymore, giving me an error. I wonder if there is cleaner syntax to use here. Thanks.

采纳的回答

Bruno Luong
Bruno Luong 2022-10-24
Use mode command
[v,f]=mode([ 2 3 4 5 5 5 6 7 7])
v = 5
f = 3
  3 个评论
Josue Ortega
Josue Ortega 2022-10-24
Ah sorry I understand now why I wanted that. I do not want the most common value, I want the most common value of each column that is not zero.
A=[ 1 2 0 3;
2 0 3 4]
I want the answer to be 2.
Bruno Luong
Bruno Luong 2022-10-24
I don't like moving question. I't a waste of time for me. I'll deltete my answer no point to comment further.

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