How can I change the Nan values in a matrix by the values in cells array?

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Hajar Alshaikh
Hajar Alshaikh 2022-11-1
评论： Hajar Alshaikh 2022-11-1
f=[1 nan 3 4 5 6;nan 3 nan 5 6 7;3 nan 5 6 nan 8; 4 5 6 7 8 nan;5 6 nan 8 9 0;6 7 8 nan 0 2]
% I want to replace each nan values by one of the following data
data=[8 0 5 9 7 3 6 4]
Input_variables = num2cell(data)
Input_variables{:}
% it works till here. Then, when I want to have the replacment:
f(Input_variables{:})
% I got this error:
Index in position 1 exceeds array bounds. Index must not exceed 6.

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采纳的回答

VBBV
VBBV 2022-11-1
f(pt) = cell2mat(data)
Use cell2mat
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VBBV
VBBV 2022-11-1
编辑：VBBV 2022-11-1
f(pt) = cell2mat(double(var))
Ok. That's because the above input is incorrect since the cell2mat takes cell arrays as input and converts to numeric array . But double(var) is not a cell array data type. It's already numeric,hence it's shows error when it encounters incorrect brace such as ( or [ Cell arrays begin with '{'. e.g. in this line
f={1 nan 3 4 5 6;nan 3 nan 5 6 7;3 nan 5 6 nan 8; 4 5 6 7 8 nan;5 6 nan 8 9 0;6 7 8 nan 0 2};
Hope this clears your doubt

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更多回答（1 个）

Akira Agata
Akira Agata 2022-11-1
Ran in:
If you want to replace NaN by the given value in linear index order, the following will be one possible solution:
% Given matrix
f = [...
1 nan 3 4 5 6;...
nan 3 nan 5 6 7;...
3 nan 5 6 nan 8;...
4 5 6 7 8 nan;...
5 6 nan 8 9 0;...
6 7 8 nan 0 2];
% Given data value
data = [8 0 5 9 7 3 6 4];
% Linear index of NaNs in the matrix f
pt = find(isnan(f));
% Replace NaN by data value
f(pt) = data;
% Show the result
disp(f)
1 0 3 4 5 6 8 3 9 5 6 7 3 5 5 6 6 8 4 5 6 7 8 4 5 6 7 8 9 0 6 7 8 3 0 2
  2 个评论
Hajar Alshaikh
Hajar Alshaikh 2022-11-1
I got this error:
Error using indexing
Invalid indexing or function definition. Indexing must follow MATLAB indexing. Function arguments must be symbolic variables, and function body must be sym expression.
I will copy the code from the begining:
f=[1 nan 3 4 5 6;nan 3 nan 5 6 7;3 nan 5 6 nan 8; 4 5 6 7 8 nan;5 6 nan 8 9 0;6 7 8 nan 0 2]
numnan=8 % number of nan in a matrix
for s =1:numnan
var(s) =min(min(f,[],'omitnan'))+(max(max(f,[],'omitnan'))-min(min(f,[],'omitnan')))*rand();
end
double(var)
data= num2cell(double(var))
pt = find(isnan(f))
% Replace NaN by data value
f(pt) = data

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