Need to flip a function and pass it through fminbnd to get the max, function has multiple agruements

16 次查看（过去 30 天）
D
D 2011-10-16
I'm trying to use fminbnd to find the max value of a function that has multiple arguements. I know I need to flip the function so the max becomes the minimum, but I can't seem to get the syntax for it, I can't even pass the function through correctly without flipping it.
v0 = 20;
th0 = 45;
h0 = 5;
g = 9.81;
t = linspace(0,4,400);
max = fminbnd(height(t,v0,th0,h0)*(-1),0,4)
%%-----------------------
function [x,y,vx,vy] = trajectory(t,v0,th0,h0,g)
if nargin<=4, g = 9.81; end
if nargin<=3, h0 = 0; end
if nargin==2, th0 = 90; end
th0 = th0*pi/180;
x = v0*cos(th0)*t;
y = h0 + v0*sin(th0)*t - 1/2*g*t.^2;
vx = v0*cos(th0);
vy = v0*sin(th0) - g*t;
%%-------------------------
function y = height(t,v0,th0,h0)
[x,y] = trajectory(t,v0,th0,h0);

请先登录，再回答此问题。

采纳的回答

D
D 2011-10-16
Found the solution with the following code:
tmax = fminbnd(@(t) height(t,v0,th0,h0)*(-1),0,4);
hmax = height(tmax,v0,th0,h0);

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Construct and Work with Object Arrays 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by