i have arrays of size 234X64X8, 234X64X8,234X64X8 and 234X64X8 inside a cell of size 4X1. i want it to be a shape of 936X256X32 as a 1X1 cell. how to do?

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ANUSAYA SWAIN
ANUSAYA SWAIN 2022-11-2
评论： Walter Roberson 2022-11-2

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Walter Roberson
Walter Roberson 2022-11-2
Ran in:
Suppose you have
A = [1 2 3; 4 5 6]
A = 2×3
1 2 3 4 5 6
B = [7 8 9; 10 11 12]
B = 2×3
7 8 9 10 11 12
size(A), size(B)
ans = 1×2
2 3
ans = 1×2
2 3
What are the ways you can arrange them?
C1 = cat(1, A, B), size(C1)
C1 = 4×3
1 2 3 4 5 6 7 8 9 10 11 12
ans = 1×2
4 3
C2 = cat(2, A, B), size(C2)
C2 = 2×6
1 2 3 7 8 9 4 5 6 10 11 12
ans = 1×2
2 6
C3 = cat(3, A, B), size(C3)
C3 =
C3(:,:,1) = 1 2 3 4 5 6 C3(:,:,2) = 7 8 9 10 11 12
ans = 1×3
2 3 2
So when you concatenate them together, the dimension you concatenate along becomes the sum of the input sizes in that dimension, and the remaining dimensions remain the length they were. Putting together two 2 x 3 arrays does not give you a 4 x 6 array -- at least not normally.
You can deliberately code concatenating them together repeatedly, using multiple copies of the input to produce something that is larger in each dimension -- but is that really what you want to do?
  2 个评论
ANUSAYA SWAIN
ANUSAYA SWAIN 2022-11-2
I want 4 arrays of size 234X64X8 to be of size 936X256X32. Is it possible to do so. like I am saying after concatenating all the 4 arrays the size should be (234x4=936),(64X4=256),(8X4=32)
Walter Roberson
Walter Roberson 2022-11-2
It is certainly possible to do, but we need you to confirm that it is acceptable that there will be 16 copies of each array.
big_array = cell2mat(repmat(hDp, 1, 4, 4) );

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Maik
Maik 2022-11-2
编辑：Maik 2022-11-2
% Code for Cell Concatenation - Input Size(234x64x8)
Arr = ones(234,64,8);
cellArr = {Arr, Arr, Arr, Arr}';
% Concatenation Across Row Dimension - Size (934x64x8)
cellRowCat = cat(1,cellArr{:});
% Concatenation Across Column Dimension - Size (234x256x8)
cellColCat = cat(2,cellArr{:});

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