Relocate element from a row to another

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Giannakis Stoukas
Giannakis Stoukas 2015-3-21
编辑： dpb 2015-3-22
Hello,i want to relocate an element from a row to an another and delete the other row.For example i have the matrix
A=[1 2 4 8 3 1;
1 9 7 6 1 ;
1 5 1 ]
and i want to relocate the 5 so i will have the matrix
A=[1 2 4 8 3 1;
1 9 7 5 6 1]
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the cyclist
the cyclist 2015-3-22
It's not possible to understand the rule you want to follow, from the one example you give.
Giannakis Stoukas
Giannakis Stoukas 2015-3-22
Actually it is a problem of local search algorithm,and it is too complicated it explain it from here. I just wanted the orders to move the element 5 between 7 and 6,and move all the other elements one position right.The rule to delete a row is "if the row has only zeros or ones,delete it",and i want the orders to do it.I know i am not very comprehensible,but it is a bit complicated to explain all the theory.

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回答（2 个）

the cyclist
the cyclist 2015-3-22
A=[1 2 4 8 3 1;
1 9 7 6 1 0;
1 5 1 0 0 0]
A = [A(1,:);
A(2,1:3) A(3,2) A(2,4:5)]
This is my best guess at what you want.
dpb
dpb 2015-3-22
编辑：dpb 2015-3-22
Well, it's not possible to write anything except the specific answer without a definition of the logic. Anything else is indiscernible from magic, not science.
But, let's see, addressing the question as asked...
>> id76=sub2ind(size(A'),4,2);
>> id5=sub2ind(size(A'),2,3);
>> B=reshape(A',1,[]);
>> B=reshape([B(1:id76-1) B(id5) B(id76:id5-1) B(id5+1:end)],size(A,2),[]).';
>> B(all(B==0|B==1,2),:)=[]
B =
1 2 4 8 3 1
1 9 7 5 6 1
>>
Needless to say, to make this of much use in general you'll have to have rules to locate the magic numbers used to compute the indices id5 and id76

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