How can I fix "Index in position 2 exceeds array bounds" in for loop ?

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Rajeev Kumar
Rajeev Kumar 2022-11-7
编辑： Joan 2022-11-8
Code:
A= datafile
sumArray = [];
for c = 1:length(A)
col = A(:,c);
sum1 = rms(A(:,c));
sumArray = [sumArray,sum1];
end
s=sumArray'
Attached file = A
Error : Index in position 2 exceeds array bounds (must not exceed 11).

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采纳的回答

CHIRANJIT DAS
CHIRANJIT DAS 2022-11-7
@Rajeev Kumar You are giving dimension of row in the for loop. Perhaps you can replace length(A) with size(A,2). Revised code looks like the below one..
sumArray = [];
for c = 1:size(A,2)
col = A(:,c);
sum1 = rms(A(:,c));
sumArray = [sumArray,sum1];
end
s=sumArray'
Cheers

更多回答（2 个）

Askic V
Askic V 2022-11-7
编辑：Askic V 2022-11-7
This is because you're not using length correctly. In fact it is not a good idea to use length when working with matrices.
In your special case, please have a look at the code:
load A.mat
% A is a matrix with dimensions: 1024x11
[nrRows, nrCols] = size(A)
ll = length(A)
I hope you understand now. You have only 11 columns in a matrix, but you're trying to iterate loop from 1 to 1024, where in fact 1024 is the number of rows.
Joan
Joan 2022-11-7
编辑：Joan 2022-11-8
W=cell(p,1);
for j=1:(p-1);
w=A(index(j):index(j+1)-2);
W{j}=w;
W2=cell(p,1);
for j=1:(p-1);
w2=A(index(j):index(j+1)-2);
W2{j}=w2
end
Z=
cell
(p,1);
for ii=1:p
P1=W{ii,1};
Z{ii,1}=P1(3:3:end);
end
for ii=1:p
P2=Z{ii,1};
if P2(end,1)>0
W2(ii,1)={[]};
end
end

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