solve residue by matlab

plz help me ....
how can I solve this problem by using residue by matlab :
25cos(πz)/((2z+1)^2 (z-2)^2 )
plz help me .. thank u .

回答(2 个)

If you have the Symbolic Math Toolbox, use the partfrac funciton:
syms z
f = 25*cos(pi*z)/((2*z+1)^2 * (z-2)^2 );
pf = partfrac(f, z)
produces:
pf =
cos(pi*z)/(z - 2)^2 - (4*cos(pi*z))/(5*(z - 2)) + (8*cos(pi*z))/(5*(2*z + 1)) + (4*cos(pi*z))/(2*z + 1)^2

4 个评论

thank u ...but I want the value of residue at (z=2 and z=-0.5) how can I find it?
The ‘pf’ expression provides you with the partial fraction evaluated at exactly those values. If you substitute them in for ‘z’ in that expression, you will get an infinite result for each, as expected.
but when I enter : syms z
f = 25*cos(pi*z)/((2*z+1)^2 * (z-2)^2 );
pf = partfrac(f, z)
in matlab , matlab give me error ...my matlab version is R2010a
According to the online documentation, partfrac was introduced in R2015a, so you wouldn’t have it in R2010a.
I posted the result as ‘pf’ in my Answer, so you have the result of the partfrac operation without having to have the function in your version.

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Konstantinos Sofos
Konstantinos Sofos 2015-3-24

0 个投票

I would suggest to use L'Hôpital's rule but you could use also the following Adaptive numerical limit (and residue) estimation

2 个评论

I want residue of complex numbers .. plz help me
Have a look in the link that i attached you before...
for your given example
f = @(z) 25*cos(pi*z)./((2*z+1).^2 .* (z-2).^2 )

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