Repeat resampling with replacement process several times

Question

stelios loizidis 2022-11-21

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1858088-repeat-resampling-with-replacement-process-several-times

评论： stelios loizidis 2022-11-21

采纳的回答： VBBV

在 MATLAB Online 中打开

Hello,

I have the below code for resampling with replacement.

res1 = [];
res2 = [];
 
 % centerd matrix size:2X7
cen1=centered(1,:); 
cen2=centered(2,:);
for j=1:7
    res1_temp=cen1(randi(7,1));
    res1= [res1 res1_temp];
    %    
    res2_temp=cen2(7,1));
    res2= [res2 res2_temp];      
end   
res_total=[res1; res2]; % 2X7

Now I have to repeat this process 170 times because centered matrix size is 170X7. That is, must have

re1=[];
res2=[];
.......
res170[];
......
res_total=[res1;res2,.....
res170];    

and the res_total should be 170X7. How can I as easy as possible?

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Answer 1

VBBV 2022-11-21

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1858088-repeat-resampling-with-replacement-process-several-times#answer_1106813

编辑：VBBV 2022-11-21

在 MATLAB Online 中打开

res1 = [];
res2 = [];
centered = rand(170,7) 
centered = 170×7
    0.6558    0.6340    0.7993    0.3911    0.8091    0.8170    0.1949
    0.9049    0.7951    0.6934    0.1121    0.0001    0.1897    0.4469
    0.3652    0.0276    0.8570    0.7298    0.7666    0.3056    0.2107
    0.9367    0.4151    0.2733    0.7628    0.5691    0.6688    0.8626
    0.6983    0.4839    0.8889    0.4091    0.7523    0.3580    0.3595
    0.9022    0.9422    0.6523    0.8360    0.9986    0.3244    0.6809
    0.0640    0.9521    0.1633    0.6885    0.4294    0.0889    0.3304
    0.5681    0.7248    0.8518    0.8903    0.8060    0.3555    0.2800
    0.3060    0.6259    0.1338    0.7183    0.2156    0.2771    0.4144
    0.2730    0.7219    0.0963    0.6360    0.6344    0.2485    0.8829
 % centerd matrix size:2X7
% cen1=centered(1,:); 
% cen2=centered(2,:);
for j=1:85
    cen1 = centered(j,:);
    res1(j,:) = cen1;
    %    
    cen2 = centered(j+85,:);
    res2(j,:) = cen2;      
end   
res_total=[res1; res2] % 2X7
res_total = 170×7
    0.6558    0.6340    0.7993    0.3911    0.8091    0.8170    0.1949
    0.9049    0.7951    0.6934    0.1121    0.0001    0.1897    0.4469
    0.3652    0.0276    0.8570    0.7298    0.7666    0.3056    0.2107
    0.9367    0.4151    0.2733    0.7628    0.5691    0.6688    0.8626
    0.6983    0.4839    0.8889    0.4091    0.7523    0.3580    0.3595
    0.9022    0.9422    0.6523    0.8360    0.9986    0.3244    0.6809
    0.0640    0.9521    0.1633    0.6885    0.4294    0.0889    0.3304
    0.5681    0.7248    0.8518    0.8903    0.8060    0.3555    0.2800
    0.3060    0.6259    0.1338    0.7183    0.2156    0.2771    0.4144
    0.2730    0.7219    0.0963    0.6360    0.6344    0.2485    0.8829

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VBBV 2022-11-21

在 MATLAB Online 中打开

May be you mean this instead

% res1 = [];
% res2 = [];
centered = rand(170,7); 
 
for j=1:170
     res_total(j,:)=centered(randi(j),:);  
end
res_total
res_total = 170×7
    0.4400    0.2235    0.8825    0.6564    0.4160    0.3429    0.0489
    0.4400    0.2235    0.8825    0.6564    0.4160    0.3429    0.0489
    0.0892    0.7041    0.9296    0.5553    0.7713    0.8969    0.5811
    0.4400    0.2235    0.8825    0.6564    0.4160    0.3429    0.0489
    0.0892    0.7041    0.9296    0.5553    0.7713    0.8969    0.5811
    0.0892    0.7041    0.9296    0.5553    0.7713    0.8969    0.5811
    0.1172    0.3186    0.5401    0.9210    0.5579    0.0420    0.7755
    0.7331    0.6314    0.0854    0.2315    0.7209    0.7810    0.0977
    0.8592    0.8540    0.0853    0.2848    0.9761    0.5497    0.2875
    0.7331    0.6314    0.0854    0.2315    0.7209    0.7810    0.0977