How to make the condition for checking the matrix value ?

1 次查看（过去 30 天）
Akash Pal
Akash Pal 2022-11-26
评论： Akash Pal 2022-11-28
function [popnew1,mutated] =mutation(A,Pm)
mutated = find(rand(size(A))<Pm);
popnew1 = A;
% Why my this condition is not working
if A(mutated)== 1
popnew1(mutated) = 2-A(mutated);
else
popnew1(mutated) = 1-A(mutated);
end
%
end
Please Help me why my this condition part is not working Where A is 3x8 matrix and Pm=0.1 .
Where is the problem in my condition ?

请先登录，再回答此问题。

采纳的回答

VBBV
VBBV 2022-11-26
popnew1 = 2-A(mutated);
  10 个评论
显示 8更早的评论
VBBV
VBBV 2022-11-27
if A(mutated) == 1
popnew1(mutated) = 2-popnew1(mutated); % in place of A put popnew1
else
popnew1(mutated) = 1-popnew1(mutated); % in place of A put popnew1
end

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 MATLAB Compiler SDK 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by