Rearranging matrix of sth elements

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Dear community,
I have a 1x1716 array that I would like to rearrange but I also would like to keep the 1x1716 matrix shape. I need to take a cell every 66th position and after finishing going on starting in position 2 and then 67 (1+66),133,199, etc... and continue with position 3, 68,134,200, etc... Could you help me?
I can write an example with a simpler matrix arranged every 3rd position instead of 66:
A=[1 2 3 4 5 6 7 8 9 10]
B=[1 4 7 10 2 5 8 3 6 9]

采纳的回答

David Hill
David Hill 2022-11-30
n=1:1716;
N=[];
for k=1:66
N=[N,n(k:66:end)];
end

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