How to find the average of 3D matrices in a cell?

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Nilesh
Nilesh 2022-12-1
评论： Walter Roberson 2022-12-2
Hello everyone,
I wish to average the 3D matrices in a cell array?
Each is a 2048 by 2048 by 100 matrix, which looks like this:
What I wish is to average each 3D matrix over the z axis (over 100), as shown below.
This will eventually lead to 1 by 3 cell, but this time, only 2048 by 2048 pixels.
The code that I have used is as follows:
for iB=1:numel(B)
meanB{iB}=mean(B{iB},3); % B is the 3D matrix
end
I have cross-cheked the values, but have found that I am not getting the right values. They are much smaller than expected.
Can anyone please help with this?
Kind regards,
Anshul

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回答（1 个）

Walter Roberson
Walter Roberson 2022-12-1
The code you already have should work. Or you could use the more compact
meanB = cellfun(@(b) mean(b,3), B, 'uniform', 0);
If the values are much smaller than expected, then re-check by commanding
format long g
and then examining the contents at the command line (not in the variable browser.)
  2 个评论
Nilesh
Nilesh 2022-12-2
Okay thank you very much.
I am still not getting the right values. Would you know if this is the correct way to create the 1 by 3 cell of 3D matrices (as shown in the first image). To do so, I have used the following:
filenum=[30, 35, 40]
B{filenum}(:,:,K)=A;%where K is length of images (100 in this case), and A reads each individual image
B=B(~cellfun('isempty',B))%Removes empty matrices
Some background imformation, there are three folders each contain 100 2D images, A is a function that reads all the images from each folder. B is the above matrix shown in the first diagram above.
I doubt this might be where the problem is coming from.
Walter Roberson
Walter Roberson 2022-12-2
That looks like it would work to create a 1 x something cell array. K would need to be varying from 1 to 100 .

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