too many output arguments, ploting loop function

Question

Lasfitri Rosanty Sinaga 2022-12-5

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1871002-too-many-output-arguments-ploting-loop-function

评论： Lasfitri Rosanty Sinaga 2022-12-5

Hi, I need completely help. I want to plot kind of 3D function with loop based on following codes (it's cut off so I dont copied all)

So, basically I want to plot x,y,z (lifetime,efficiency,H2MSAeff) from the function H2MSA_conversion.m . That function hat the head

function [H2MSA_eff]=H2MSA_conversion(senslife,eta,msaprice).

But I got error message :

Error using H2MSA_conversion

Too many output arguments.

Error in H2MSAeff_basecase_plot (line 87)

[a,b]=H2MSA_conversion(lifetime(j),efficiency(i), msaprice);

The codes I use for ploting:

%sensitivity analysis
%lifetime and efficiency
lifetime=linspace(30,5,20);
efficiency=linspace(0.3,0.05,20);
l=length(lifetime);
e=length(efficiency);
H2MSAeff=zeros(l,e);   %EMPHASIS
for i=1:e
    for j=1:l
        [a,b]=H2MSA_conversion(lifetime(j),efficiency(i), msaprice);  %EMPHASIS
        plot_H2MSA_conversion=[a,b];
        H2MSAeff(i,j)=plot_H2MSA_conversion(key);
    end
end
Unrecognized function or variable 'msaprice'.
efficiency=efficiency*100;
[Lifetime,Efficiency,H2MSAeff]=griddata(lifetime,efficiency,H2MSAeff,linspace(min(lifetime),...
    max(lifetime),100)',linspace(min(efficiency),max(efficiency),100),'linear');
if figurekey==1
    Lmin=min(min(H2MSAeff));Lmax=max(max(H2MSAeff));
    L=[Lmin,100,1000,10000,30000,40000,Lmax];
    L=roundn(L,-1);
    [C,h]=contourf(Lifetime,Efficiency,H2MSAeff,L,'ShowText','on','color','white');
    clabel(C,h,'FontSize',13,'Color','w'); %Set curve label font size
    colorbar;
    colormap(parula);
    
    xlabel('Lifetime(year)');
    ylabel('STH Efficiency(%)');
    
    m = get(gca,'XTickLabel'); % Set font size of axis
    set(gca,'XTickLabel',m,'fontsize',13);
end
if figurekey~=1
end

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Answer 1

Walter Roberson 2022-12-5

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https://ww2.mathworks.cn/matlabcentral/answers/1871002-too-many-output-arguments-ploting-loop-function#answer_1119997

在 MATLAB Online 中打开

We do not have your functions. What we do have is your line of code

[a,b]=H2MSA_conversion(lifetime(j),efficiency(i), msaprice);

which expects H2MSA_conversion to return two outputs, here called a and b.

And we have your statement that you have

function [H2MSA_eff]=H2MSA_conversion(senslife,eta,msaprice)

Notice that returns only a single output, here named H2MSA_eff . That would go into a in the caller, but there is no output that can go into b in the caller.