dimension mismatch??! i cant see how this can be a dimension mismatch?
1 次查看(过去 30 天)
显示 更早的评论
A.textdata(:,3) holds a large set of dates
I am trying to do this:
for i=1:size(A.textdata)
Dates(i,1) = datenum(A.textdata(i,3),'dd-mm-yyyy HH:MM:SS');
Dates2(i,1) = datestr(Dates(i,1),'dd-mm-yyyy ')
end
but i am getting thins error:
> ??? Subscripted assignment dimension mismatch.
Error in ==> Load at 12 Dates2(i,1) = datestr(Dates(i,1),'dd-mm-yyyy ')
Why is that? i cant see how there can be any dimension mismatches??
0 个评论
采纳的回答
Daniel Shub
2011-10-19
The problem is that
Dates2(i,1)
is a scalar, but
datestr(Dates(i,1),'dd-mm-yyyy ')
returns a string with length 10.
Dates2(i,:) = datestr(Dates(i,1),'dd-mm-yyyy ');
should work.
0 个评论
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Dialog Boxes 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!