Calculate consecutive values from annual data to monthly have a yearly timetable (events(1X365)) and I want to find how many consecutive values are equal to 1 for every mont

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Ancalagon8
Ancalagon8 2022-12-11
评论： Mathieu NOE 2022-12-13
I have a yearly timetable (events(1X365)) and I want to find how many consecutive values are equal to 1 for every month. Right now the below code calculates the consecutive ones (1) for January:
f= find(diff([0; (events{1,1}); 0]==1));
events_Jan= [f(1:2:end-1) f(2:2:end)-1 (f(2:2:end)-1-(f(1:2:end-1))+1)];
Max_conseq_for_January=max(events_Jan(:,3));
How can I create a loop for all the 12 months?

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Mathieu NOE
Mathieu NOE 2022-12-12
hello
well a simple for loop will do the job
your result in now an array of length 12 : Max_conseq
load('events.mat')
for m =1:numel(events) % loop over month
f= find(diff([0; events{m} ; 0]==1));
events_this_month= [f(1:2:end-1) f(2:2:end)-1 (f(2:2:end)-1-(f(1:2:end-1))+1)];
Max_conseq(m) = max(events_this_month(:,3));
end
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