Maintain values inside loop

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Ancalagon8
Ancalagon8 2022-12-12
评论： Ancalagon8 2022-12-13
I need help debugging this part of my code, from annual data i want to create 12 timetables , one for each month. Right now the result shows only the last month (December), without keeping the previous ones.
for i =1:12
resultsperMonth_=timetable(Datespermonth{i,1},dataperMonth{i,1})
end
Any ideas how to correct the above loop?

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Bora Eryilmaz
Bora Eryilmaz 2022-12-12
编辑：Bora Eryilmaz 2022-12-12
Ran in:
Store the results in a vector of results instead of just keeping a scalar result for the last one. See the "{i}" index below:
for i = 1:12
resultsperMonth_{i} = timetable(Datespermonth{i,1},dataperMonth{i,1})
end
You can do something like this:
A = {};
for i = 1:5
A{i} = timetable;
end
A
A = 1×5 cell array
{0×0 timetable} {0×0 timetable} {0×0 timetable} {0×0 timetable} {0×0 timetable}
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Bora Eryilmaz
Bora Eryilmaz 2022-12-12
编辑：Bora Eryilmaz 2022-12-12
Then, you can use a cell array to store the results. I've updated the code above.

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