can someone help me to write the code ?

Question

Majid 2022-12-13

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评论： Majid 2022-12-14

Hi all

i'm trying to execute my program in matlab in order to ckeck results after a number of iteration under two variables B1 and B2, which are two row vectors with same dimension but i will focus only for the first element of each of them, it means i want to do a number of iteration in order to change the first element of each vector,

so i wrote my code as follow : here B1 should be started from 0 and B2 from 1000.

A_100_iteration = cell(51,1);
Result_100_iteration = cell(51,1);
for ib = 1:51
    B1(1) = (ib-1)*20;
    %code of the first variable
    
    for ib1 = 50:-1 :1
        B2(1) = (ib)*20;
   
     %code of the first variable
        for n = 1:100
            %my program is here 
            
            
            A_100_iteration{ib}=[A_100_iteration{ib},A] ; 
            Result_100_iteration{ib}=[Result_100_iteration{ib},Result] ; %
        end
        B1_100_iteration{ib} = [B1_100_iteration{ib},B1];
        B2_100_iteration{ib1} = [B2_100_iteration{ib1},B2];
    end
end 

the code doesn't work as i want, in each time the dimension of each vector has been changed,knowing that when i did same code for only B1 it works well.

any suggestion please

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Answer 1

Torsten 2022-12-13

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https://ww2.mathworks.cn/matlabcentral/answers/1877312-can-someone-help-me-to-write-the-code#answer_1127077

在 MATLAB Online 中打开

A_100_iteration = cell(51,50,1);
Result_100_iteration = cell(51,50,1);
B1_100_iteration = cell(51,50,1);
B2_100_iteration = cell(51,50,1);
for ib = 1:51
    B1(1) = (ib-1)*20;
    %code of the first variable
    
    for ib1 = 1:50
        B2(1) = (51-ib1)*20;
        
        %code of the first variable
        for n = 1:100
            %my program is here 
            
            
            A_100_iteration{ib,ib1}=[A_100_iteration{ib,ib1},A] ; 
            Result_100_iteration{ib,ib1}=[Result_100_iteration{ib,ib1},Result] ; %
        end
        B1_100_iteration{ib,ib1} = [B1_100_iteration{ib,ib1},B1];
        B2_100_iteration{ib,ib1} = [B2_100_iteration{ib,ib1},B2];
    end
end 

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Majid 2022-12-13

在 MATLAB Online 中打开

@Torsten thank you for your reply, i need just vectors for each A,Result, B1 and B2, with the modification you mentioned i get matrices for each one, when i remove "ib1" as following and i ran B2 also for 51 iterations, i get 51 rows for both B1 and B2, in each row i have the intial vector, but the problem each vector was repeated 51 times , it means instead of seeing the intial dimension of B1 and B2, i see that it was multiplied by 51.

so i'm asking when i put exactly the last two lines in my code in order to eliminate the repetition of the same vector.

A_100_iteration = cell(51,1);
Result_100_iteration = cell(51,1);
B1_100_iteration = cell(51,1);
B2_100_iteration = cell(51,1);
for ib = 1:51
    B1(1) = (ib-1)*20;
    %code of the first variable
    
    for ib1 = 1:51
        B2(1) = (51-ib1)*20;
        
        %code of the first variable
        for n = 1:100
            %my program is here 
            
            
            A_100_iteration{ib}=[A_100_iteration{ib},A] ; 
            Result_100_iteration{ib}=[Result_100_iteration{ib},Result] ; %
        end
        B1_100_iteration{ib} = [B1_100_iteration{ib},B1];
        B2_100_iteration{ib} = [B2_100_iteration{ib},B2];
    end
end 

Torsten 2022-12-14

编辑：Torsten 2022-12-14

在 MATLAB Online 中打开

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https://de.mathworks.com/learn/tutorials/matlab-onramp.html

?

Only two hours - I think it would help you.

%Generate cell array of row vectors
A_100_iteration = cell(51,1);
for i = 1:51
  A_100_iteration{i} = [2 3 4 5 6 7];
end
%Extract last element from each cell
Array_last_element = zeros(51,1);
for i = 1:51
  Array_last_element(i) = A_100_iteration{i}(end);
end
Array_last_element
Array_last_element = 51×1
     7
     7
     7
     7
     7
     7
     7
     7
     7
     7

Majid 2022-12-14

okay , thank you very much

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can someone help me to write the code ?

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