Losing resolution after transformation using imwarp

6 次查看(过去 30 天)
I'm working on a camera calibration through a series of pictures of a checkerboard. The original size of the images are 2048x2448. After transformation, the resulting corrected image with 'imwarp' is only 310x367. Although the transformation seems correct, the resolution seems very low to me and I'm wondering why the resolution dropped so significantly. The transformation I performing is some minor intrinsic/extrinsic corrections.
Here is the code used. The variable 'cameraParams' is obtained after successfully using the "camera calibration tool" from the "Computer Vision Toolbox v10.2". Both the raw image (.bmp) and the 'cameraParams.mat' are attached.
Thanks for the help.
[im_a, newOrigin] = undistortImage(imread(strcat(figlocation,fig_name)), cameraParams);
imagePoints = squeeze(cameraParams.ReprojectedPoints(:,:,end));
tf = fitgeotrans(imagePoints,cameraParams.WorldPoints,'projective');
[xf1,xf1_ref] = imwarp(im_a,tf,'cubic');
im_b=rot90(xf1);
figure;imshow(im_a);title('image')
figure;imshow(im_b);title('transformed image')

采纳的回答

Matt J
Matt J 2023-1-5
load cameraParams
im0=imread('b8-12212022142637-2006.Bmp');
[im_a, newOrigin] = undistortImage(im0, cameraParams);
imagePoints = squeeze(cameraParams.ReprojectedPoints(:,:,end));
tf = fitgeotrans(imagePoints,cameraParams.WorldPoints,'projective');
[~,xf1_ref] = imwarp(im_a,tf,'cubic');
xf1_ref.ImageSize=flip(size(im_a));
[xf1,xf1_ref] = imwarp(im_a,tf,'cubic','OutputView',xf1_ref);
im_b=rot90(xf1);
figure;imshow(im_a);title('image')
figure;imshow(im_b);title('transformed image')
  2 个评论
Jos Muller
Jos Muller 2023-1-5
编辑:Jos Muller 2023-1-5
Thanks Matt,
Neat solution.
Sofar I understand from your awnser, imwarp default changes the imageSize of the projected image to 367x310. To prevent this, you first generate a 'imref2d' object where you manually change the image size. By then explicitly mention the 'outputview' parameter, 'imwrap' retains the image resolution. Is this correct?
However, aside the resolution, the projection from pixels to actual distances through worldpoints seems to be affected by this solution as well. In the projection I want the checkerboard to correspond to 20 mm distance (as in 'cameraParams.WorldPoints' mat-file. However, when measuring the distance in imtool(im_b), this now looks like 138 (mm?)
Best,
Jos
Matt J
Matt J 2023-1-5
编辑:Matt J 2023-1-5
imtool() is assuming the pixel sizes are 1 mm. I'm not aware if there is a way to tell it that the actual pixel sizes are about 0.15 mm,
xf1_ref =
imref2d with properties:
XWorldLimits: [-76.6815 233.3185]
YWorldLimits: [-105.2473 261.7527]
ImageSize: [2448 2048]
PixelExtentInWorldX: 0.1514
PixelExtentInWorldY: 0.1499
ImageExtentInWorldX: 310
ImageExtentInWorldY: 367
XIntrinsicLimits: [0.5000 2.0485e+03]
YIntrinsicLimits: [0.5000 2.4485e+03]

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Display Image 的更多信息

产品


版本

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by