Remove '00' the first two digit to '0' in cell

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eko supriyadi
eko supriyadi 2023-1-12
评论： Walter Roberson 2023-1-12
Hi community,
Suppose i have array in cell:
ab={'10300' '20257' '30073' '40080' '55011' '82132' '0' '0' '0'; '10321' '20258' '30084' '40091' '56024' '00822' '0' '0' '0'};
the question how change '00822' that contain '00' the first two digit to '0', so the result i want is:
ab={'10300' '20257' '30073' '40080' '55011' '82132' '0' '0' '0'; '10321' '20258' '30084' '40091' '56024' '0' '0' '0' '0'};
thx

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采纳的回答

Walter Roberson
Walter Roberson 2023-1-12
Ran in:
Are you sure you do not want to remove all leading zeros (leaving, of course a lone 0) ?
ab={'10300' '020257' '30073' '00080' '55011' '82132' '0' '00' '0'; '10321' '20258' '30084' '40091' '56024' '00822' '0' '0' '0'}
ab = 2×9 cell array
{'10300'} {'020257'} {'30073'} {'00080'} {'55011'} {'82132'} {'0'} {'00'} {'0'} {'10321'} {'20258' } {'30084'} {'40091'} {'56024'} {'00822'} {'0'} {'0' } {'0'}
ab_remove_00_only = regexprep(ab, '^00(?=\d)', '')
ab_remove_00_only = 2×9 cell array
{'10300'} {'020257'} {'30073'} {'080' } {'55011'} {'82132'} {'0'} {'00'} {'0'} {'10321'} {'20258' } {'30084'} {'40091'} {'56024'} {'822' } {'0'} {'0' } {'0'}
ab_remove_all_leading_0 = regexprep(ab, '^0+(?=\d)', '')
ab_remove_all_leading_0 = 2×9 cell array
{'10300'} {'20257'} {'30073'} {'80' } {'55011'} {'82132'} {'0'} {'0'} {'0'} {'10321'} {'20258'} {'30084'} {'40091'} {'56024'} {'822' } {'0'} {'0'} {'0'}
  1 个评论
Walter Roberson
Walter Roberson 2023-1-12
Ran in:
After re-reading the question:
ab={'10300' '020257' '30073' '00080' '55011' '82132' '0' '00' '0'; '10321' '20258' '30084' '40091' '56024' '00822' '0' '0' '0'}
ab = 2×9 cell array
{'10300'} {'020257'} {'30073'} {'00080'} {'55011'} {'82132'} {'0'} {'00'} {'0'} {'10321'} {'20258' } {'30084'} {'40091'} {'56024'} {'00822'} {'0'} {'0' } {'0'}
ab_zap_00 = regexprep(ab, '^00.*', '0')
ab_zap_00 = 2×9 cell array
{'10300'} {'020257'} {'30073'} {'0' } {'55011'} {'82132'} {'0'} {'0'} {'0'} {'10321'} {'20258' } {'30084'} {'40091'} {'56024'} {'0' } {'0'} {'0'} {'0'}

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更多回答（1 个）

Karim
Karim 2023-1-12
Ran in:
Hi, you can do that with the startswith function of matlab:
ab = {'10300' '20257' '30073' '40080' '55011' '82132' '0' '0' '0'; '10321' '20258' '30084' '40091' '56024' '00822' '0' '0' '0'}
ab = 2×9 cell array
{'10300'} {'20257'} {'30073'} {'40080'} {'55011'} {'82132'} {'0'} {'0'} {'0'} {'10321'} {'20258'} {'30084'} {'40091'} {'56024'} {'00822'} {'0'} {'0'} {'0'}
% use the 'starts with' function to determine the locations
TF = startsWith(ab,"00")
TF = 2×9 logical array
0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0
% replace with a single '0'
ab(TF) = {'0'}
ab = 2×9 cell array
{'10300'} {'20257'} {'30073'} {'40080'} {'55011'} {'82132'} {'0'} {'0'} {'0'} {'10321'} {'20258'} {'30084'} {'40091'} {'56024'} {'0' } {'0'} {'0'} {'0'}

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