Limit length of a string

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Christian Günther
Christian Günther 2023-1-16
回答： Christian Günther 2023-1-16
Ran in:
Hello,
How can I limit the lengt of strings that I print out ?
text1 contains a sting of length 7 to 25, but I want to print a maximum of 18 charactes.
I have tried the following, but it does not work for text1:
text1='012345678901234567890123456789';
text2='01234567';
sprintf('%-18s',text1)
ans = '012345678901234567890123456789'
sprintf('%-18s',text2)
ans = '01234567 '
In the end it should look like a table.
Best regards
Christian

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采纳的回答

Christian Günther
Christian Günther 2023-1-16
Hello,
I've found the solution myself:
with this command it gests truncated to 18 characters:
sprintf('%+18.18s',text1)

更多回答（2 个）

Matt J
Matt J 2023-1-16
Ran in:
text1='012345678901234567890123456789';
text2='01234567';
text1(19:end)=''
text1 = '012345678901234567'
text2(19:end)=''
text2 = '01234567'
  2 个评论
Christian Günther
Christian Günther 2023-1-16
Hello,
Thanks for the reply.
It is working, but I need to overwrite each string before using it.
Thanks !!
Matt J
Matt J 2023-1-16
编辑：Matt J 2023-1-16
Ran in:
Wrap the steps in some function,
text1='012345678901234567890123456789';
text2='01234567';
trunctext(text1)
012345678901234567
trunctext(text2)
01234567
function trunctext(T)
T(19:end)='';
disp(T)
end

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Walter Roberson
Walter Roberson 2023-1-16
https://www.mathworks.com/help/matlab/ref/extractbefore.html
This can be used in an expression without modifying the variable. Also it can be used with string() objects as well
  1 个评论
Christian Günther
Christian Günther 2023-1-16
this is failing for text2:
text2='01234567';
sprintf('%+18s',extractBefore(text2,18))
% Error using extractBefore (line 51)
% Numeric value exceeds the number of characters in element 1.

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