How would I split a vector in two based on the data values of 1 or 0?

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Kendell
Kendell 2023-1-23
评论： Image Analyst 2023-1-23
Create two vectors from a long vector consiting of 1s and 0s. I have some data to sort and I have the values in binary form in a vector of a 43000x1 consisting of just 1s and 0s. I need to split this vector into two vectors, one consisting of 1s, and the other consisting of the 0s. This will result in two different sized vectors.

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Image Analyst
Image Analyst 2023-1-23
编辑：Image Analyst 2023-1-23
Ran in:
vec = randi([0, 1], 43000, 1)
vec = 43000×1
0 0 0 0 0 0 1 1 0 1
mask = vec == 1;
vec0 = vec(~mask);
vec1 = vec(mask);
whos vec0;
Name Size Bytes Class Attributes vec0 21552x1 172416 double
whos vec1
Name Size Bytes Class Attributes vec1 21448x1 171584 double
% Or another way
vec0 = zeros((length(vec) - nnz(vec)), 1);
vec1 = ones(nnz(vec), 1);
whos vec0
Name Size Bytes Class Attributes vec0 21552x1 172416 double
whos vec1
Name Size Bytes Class Attributes vec1 21448x1 171584 double
  2 个评论
Kendell
Kendell 2023-1-23
Thank you, that worked! I have another question to kind of add on to this one if you don't mind. Say that I have a 43000 x 50 matrix, could I organize it based on whether the first column recieved a 1 or a 0? Therefore I could get 2 Matricies. For your example, it would result in a 21448 x 50 Matrix based on 1s and a 21552 x 50 Matrix based on 0s.
Image Analyst
Image Analyst 2023-1-23
Ran in:
Not sure what you mean. A column is more than a single number.
Anyway, you can do masking on the first column and apply that to all columns:
m = randi([0, 1], 43000, 50);
% Make mask based on first column ONLY.
rowsWith1 = m(:, 1) == 1;
m0 = m(~rowsWith1, :);
m1 = m(rowsWith1, :);
whos m0;
Name Size Bytes Class Attributes m0 21326x50 8530400 double
whos m1
Name Size Bytes Class Attributes m1 21674x50 8669600 double
Note however that m0 and m1 will have a mixture of 0s and 1s in columns 2-50. Only the first column will be all 0 or all 1.

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