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Empty matrix, scalar, or vector function in loop

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Lewis HC
Lewis HC 2023-1-26
评论： Lewis HC 2023-1-30
Greetings all, I need to write a function called CLF whose input argument is x, that input argument must not have more than two dimensions. If x is an empty array, the function returns -1. If x is a scalar, the function returns 0. If x is a vector, the function returns 1 and if x is none of the above, the function returns 2, do not use isempty, isscalar, isvector, my code is as follows: thank you!
function y=CLF(x)
for a=1:n;
if x=[];
y='-1';
elseif x=a;
y='0';
elseif x=[a,a];
y='1';
else x~=a;
y='2';
end
end
end

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Walter Roberson
Walter Roberson 2023-1-26
Ran in:
MATLAB uses == for comparisons, not =
Also,
X = []
X = []
Y = 1
Y = 1
if X == []; disp('X yes 1'); end
if Y == []; disp('Y yes 1'); end
if isequal(X, []); disp('X yes 2'); end
X yes 2
if isequal(Y, []); disp('Y yes 2'); end
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Walter Roberson
Walter Roberson 2023-1-27
Ran in:
I missed a case in my examples:
isequal([], ones(1,2,3,0,5,6))
ans = logical
0
That tells you that you cannot use isequal() to generally detect empty matrices.
elseif x==x+1;
The only case that would match that would be if x consists of all infinite values (positive or negative)
elseif x==[x,x];
[x,x] is going to have more elements than x does, except in the case that x is empty. However we already showed that you cannot use == to test for empty.
You should be examining size(x) rather than any of the tests you are presently doing.

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