Epicycloid curve calculating arch length using integral method

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pauli relanderi
pauli relanderi 2023-2-7
评论： pauli relanderi 2023-2-8
Im trying to calculate the length of the Epicycloid curve.
i have the x and y coordinates right and i get the correct looking plot, but cant figure out how to calculate the length of the epicycloid curve.
I already tried to calculate, but didnt get results that make sense.
Any help would be greatly appreciated.
Here is a picture of what im calculating:
clear all
R=8;
L=6;
Alfa=2*pi;
Bertta=4*pi;
T=2*pi/Alfa;
syms t
alfa0=Alfa*t;
beta0=Bertta*t;
%%%%%%%%%%%%%%%%%%% %R Coordinates
x0(t)=R*cos(alfa0);
y0(t)=R*sin(alfa0);
%%%%%%%%%%%%%%%%%% %L Coordinates
x(t)=x0(t)+L*cos(alfa0+beta0);
y(t)=y0(t)+L*sin(alfa0+beta0);
%
%x1(t)=diff(x,t)
%y1(t)=diff(y,t)
%t0=2;
%dx=x1(t0)
%dy=y1(t0)
%s0 = @(t) sqrt( ( R.*cosd(t)+L.*cosd(3.*t) ).^2 + (R.*sind(t)+L.*sind(3.*t)).^2);
%s = integral(s0,0,2*pi)
%pit = sqrt(1+(dy/dx).^2*dx)
%lenght = integral(pit,0,2*pi)
fplot(x,y,[0,T],'linewidth',2)
title(['R = ',num2str(R),', L = ',num2str(L),', s = ',num2str(5)])
hold off
grid
axis equal
xlabel('x')
ylabel('y')

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采纳的回答

Torsten
Torsten 2023-2-7
curvelength = vpaintegral(sqrt(diff(x,t)^2+diff(y,t)^2),t,0,T)

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