invalid index in find function

Question

Timothy Dunning 2023-2-23

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1917685-invalid-index-in-find-function

编辑： Walter Roberson 2023-2-25

Wrote this function to detect a line on a .png file of a graph, read the coordinates and use them to recalculate the graph data:

function TC =  fileReadTest()
%set data at graph limits
Tfmax = 2000;
tmax = 2000;
[pixels]=imread("temp597.jpg"); % read rgb values for each pixel on graph
imshow(pixels)
[x_axes,y_axes]=ginput(2);% select axes limits (y limit then x limit)
data(2,x_axes(2)-x_axes(1)) = zeros; %define the length of the data list
for column=x_axes(1):x_axes(2) %loop for each column inside the graph
    %find the first red(ish) pixel in the column
    [row, col]=find(pixels(:,column,1)>200 && pixels(:,column,2)<50,1,'first');
    if (col == column) %append data list if red pixel is found in the column
        data(:,col) = [row;col]-[x_axes(1);y_axes(2)];
    end
end
% convert data coordinate to usable value
Tf=[Tfmax/(y_axes(1)-y_axes(2))*data(1,:);tmax/(x_axes(2)-x_axes(1))*data(2,:)];
TC=(Tf(1,:)-32)*5/9;

got the following error:

Index in position 2 is invalid. Array indices must be positive

integers or logical values.

Error in fileReadTest (line 14)

[row, col]=find(pixels(:,column,1)>200 && pixels(:,column,2)<50,1,'first');

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Steven Lord 2023-2-23

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1917685-invalid-index-in-find-function#answer_1178445

There's no guarantee that the elements of x_axes (the points that you selected using ginput) are integer values. Therefore there's no guarantee that the values assigned to your loop variable column are integer values. MATLAB can't index into the 125.3827th column (as an example) of your pixels array.

Perhaps it would be sufficient if you were to round those coordinates before using them in your loop.

3 个评论
显示 1更早的评论隐藏 1更早的评论

Steven Lord 2023-2-25

在 MATLAB Online 中打开

You can't use the short-circuiting && or || operators when either of the inputs you're operating on are non-scalars. [If you could, and the first input contained a mix of true and false values, should the second input only be evalated for those elements where their values could change what the logical operators return? That could get very messy very quickly.]

Use the non-short circuiting & or | operators instead.

x = 1:10;
y = 10:-1:1;
z = (x > 3) & (y > 4)
z = 1×10 logical array
   0   0   0   1   1   1   0   0   0   0
[x; y; z]
ans = 3×10
     1     2     3     4     5     6     7     8     9    10
    10     9     8     7     6     5     4     3     2     1
     0     0     0     1     1     1     0     0     0     0