How to fill zeros and NaNs with the average of the previous nonzero consecutive values

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Margarida
Margarida 2023-3-6
评论： Margarida 2023-3-7
Hi fellow helpers!
So, i have a column like this:
T = [0;0;1;2;3;4;NaN;4;3;0;0;0;NaN;4;2;3;0;2;0];
And everytime I have a NaN or a zero, I would like to transform them in the average of the previous nonzero consecutive values (averages in bold):
T = [0;0;1;2;3;4;2.5;4;3;3.5;3.5;3.5;3.5;4;2;3;3;2;2];
I cannot figure out how I can do this in an efficient way (without for loops, because the column has thousands of rows).
I hope you can help me out! Thanks! :)

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Matt J
Matt J 2023-3-6
编辑：Matt J 2023-3-6
Using this FEX download,
https://www.mathworks.com/matlabcentral/fileexchange/78008-tools-for-processing-consecutive-repetitions-in-vectors
T = [0;0;1;2;3;4;NaN;4;3;0;0;0;NaN;4;2;3;0;2;0];
idx=find(T,1);
[stem,T]=deal(T(1:idx-1),T(idx:end));
G=groupTrue(~isnan(T) & T~=0);
[~,~,lengths]=groupLims(groupTrue(~G),1);
T(~G)=repelem( groupFcn(@mean,T,G) ,lengths);
T=[stem;T]
T'
ans =
Columns 1 through 9
0 0 1.0000 2.0000 3.0000 4.0000 2.5000 4.0000 3.0000
Columns 10 through 18
3.5000 3.5000 3.5000 3.5000 4.0000 2.0000 3.0000 3.0000 2.0000
Column 19
2.0000
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