"Continue" in "for loop" based on trial count

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HumbleCoder
HumbleCoder 2023-3-6
评论： Voss 2023-3-9
I have the following loop set up:
X_vector = [3; -3; -9; -15; -21; -15; -9; -3; 3; 3; -3; -9; -15; -21; -21; -15; -9; -3; 3; 3; -3; -9; -15; -21; -15; -9; -3; 3;];
Y_vector = [15; 15; 15; 15; 9; 9; 9; 9; 9; 3; 3; 3; 3; 3; -3; -3; -3; -3; -3; -9; -9; -9; -9; -9; -15; -15; -15; -15;];
for k = 1 : numel(X_vector)
x = X_vector(k);
y = Y_vector(k);
% Now use x and y in some way.
end
I want the loop to run through all the X and Y vector locations but change every 5 trials to the next X_vector and Y_vector pair (e.g. from (3, 15) to (-3, 15). Do I use a continue function to this?
Thank you in advance for your help!

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采纳的回答

Voss
Voss 2023-3-6
Maybe this:
for k = 1 : numel(X_vector)
for n = 1 : 5
x = X_vector(k);
y = Y_vector(k);
% Now use x and y in some way.
end
end
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HumbleCoder
HumbleCoder 2023-3-9
The error was on my end!! Thank you so much for helping me!! Your suggestion works like a charm!
Voss
Voss 2023-3-9
You're welcome! Glad you got it to work!

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