ocr problem
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jan this is the code for read_letter
function letter=read_letter(imagn,num_letras)
% Computes the correlation between template and input image
% and its output is a string containing the letter.
% Size of 'imagn' must be 42 x 24 pixels
% Example:
% imagn=imread('D.bmp');
% letter=read_letter(imagn)
global templates
comp=[ ];
for n=1:num_letras
sem=corr2(templates{1,n},imagn);
comp=[comp sem];
end
vd=find(comp==max(comp));
%*-*-*-*-*-*-*-*-*-*-*-*-*-
if vd==1
letter='A';
elseif vd==2
letter='B';
elseif vd==3
letter='C';
elseif vd==4
letter='D';
elseif vd==5
letter='E';
elseif vd==6
letter='F';
elseif vd==7
letter='G';
elseif vd==8
letter='H';
elseif vd==9
letter='I';
elseif vd==10
letter='J';
elseif vd==11
letter='K';
elseif vd==12
letter='L';
elseif vd==13
letter='M';
elseif vd==14
letter='N';
elseif vd==15
letter='O';
elseif vd==16
letter='P';
elseif vd==17
letter='Q';
elseif vd==18
letter='R';
elseif vd==19
letter='S';
elseif vd==20
letter='T';
elseif vd==21
letter='U';
elseif vd==22
letter='V';
elseif vd==23
letter='W';
elseif vd==24
letter='X';
elseif vd==25
letter='Y';
elseif vd==26
letter='Z';
%*-*-*-*-*
elseif vd==27
letter='1';
elseif vd==28
letter='2';
elseif vd==29
letter='3';
elseif vd==30
letter='4';
elseif vd==31
letter='5';
elseif vd==32
letter='6';
elseif vd==33
letter='7';
elseif vd==34
letter='8';
elseif vd==35
letter='9';
else
letter='0';
end
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采纳的回答
Naz
2011-10-25
Check out this similar problem. Instead of having so much else ifs, do a conversion of a number to string. That is, 'A' is a 65, so, you can say letter=num2str(sv+64). In this case, if sv=1, the sum is 65 and if you do number-to-string conversion you will get an 'A'. Notice, for numbers,if you can encode the '0' as vd==27 and '9' as vd==35, it will be easier to code.
2 个评论
更多回答(1 个)
Walter Roberson
2011-10-25
The long if/else chain can be replaced by:
transtab = ['A':'Z' '1':'9'];
if vd < 1 || vd > length(transtab)
letter = '0';
else
letter = transtab(vd);
end
另请参阅
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