Covert a string to an array of individual characters.

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I apologize if my question is trivial.
I have the following datasets.The letters in each dataset represent student names enrolled in each course :
Course1=['A','B','C','E','F','G','I','P','Q'];
Course2=['B','E','F','H','K','Q','R','S','T','U','V','Z'];
Course3=['C','E','G','H','J','K','O','Q','Z'];
So for example
Course1orCourse2 = union(Course1,Course2)
Course1orCourse2 = 'ABCEFGHIKPQRSTUVZ'
Course1andCourse2 = intersect(Course1,Course2)
Course1andCourse2 = 'BEFQ'
How can I get an output in the form ['A', 'B', 'C', 'E', 'F', 'G', 'H', 'I', 'K', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'Z'] and ['B', 'E', 'F', 'G']? Thank you very much?
  1 个评论
Stephen23
Stephen23 2023-3-28
编辑:Stephen23 2023-3-28
Note that square brackets are a concatentation operator (not a list operator like in some other langauges), so your examples are just complicated ways of writing character vectors. For example, this code:
Course1 = ['A','B','C','E','F','G','I','P','Q'];
is just a longer way of writing this equivalent character vector:
Course1 = 'ABCEFGIPQ';
The same applies to your requested outputs, e.g. this:
['A', 'B', 'C', 'E', 'F', 'G', 'H', 'I', 'K', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'Z']
is exactly equivalent to this simple character vector:
'ABCEFGHIKPQRSTUVZ'
And that is already what UNION and INTERSECT are giving you: character vectors which consist of lots of individual characters. Understanding what square brackets actually do, and what character vectors are, is very important when using MATLAB:

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采纳的回答

Dyuman Joshi
Dyuman Joshi 2023-3-28
编辑:Dyuman Joshi 2023-3-28
If you need every alphabet presented individually, you will have to define them as strings.
Either manually define each input with double inverted commas
Course1=["A","B","C","E","F","G","I","P","Q"]; %similarly for Course2 and Course3
or use compose on the existing data -
Course1=['A','B','C','E','F','G','I','P','Q'];
Course2=['B','E','F','H','K','Q','R','S','T','U','V','Z'];
Course3=['C','E','G','H','J','K','O','Q','Z'];
Course1=compose("%s",Course1')';
Course2=compose("%s",Course2')';
Course3=compose("%s",Course3')'
Course3 = 1×9 string array
"C" "E" "G" "H" "J" "K" "O" "Q" "Z"
Course1orCourse2 = union(Course1,Course2)
Course1orCourse2 = 1×17 string array
"A" "B" "C" "E" "F" "G" "H" "I" "K" "P" "Q" "R" "S" "T" "U" "V" "Z"
Course1andCourse2 = intersect(Course1,Course2)
Course1andCourse2 = 1×4 string array
"B" "E" "F" "Q"

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