Covert a string to an array of individual characters.
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I apologize if my question is trivial.
I have the following datasets.The letters in each dataset represent student names enrolled in each course :
Course1=['A','B','C','E','F','G','I','P','Q'];
Course2=['B','E','F','H','K','Q','R','S','T','U','V','Z'];
Course3=['C','E','G','H','J','K','O','Q','Z'];
So for example
Course1orCourse2 = union(Course1,Course2)
Course1andCourse2 = intersect(Course1,Course2)
How can I get an output in the form ['A', 'B', 'C', 'E', 'F', 'G', 'H', 'I', 'K', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'Z'] and ['B', 'E', 'F', 'G']? Thank you very much?
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Stephen23
2023-3-28
编辑:Stephen23
2023-3-28
Note that square brackets are a concatentation operator (not a list operator like in some other langauges), so your examples are just complicated ways of writing character vectors. For example, this code:
Course1 = ['A','B','C','E','F','G','I','P','Q'];
is just a longer way of writing this equivalent character vector:
Course1 = 'ABCEFGIPQ';
The same applies to your requested outputs, e.g. this:
['A', 'B', 'C', 'E', 'F', 'G', 'H', 'I', 'K', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'Z']
is exactly equivalent to this simple character vector:
'ABCEFGHIKPQRSTUVZ'
And that is already what UNION and INTERSECT are giving you: character vectors which consist of lots of individual characters. Understanding what square brackets actually do, and what character vectors are, is very important when using MATLAB:
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Dyuman Joshi
2023-3-28
编辑:Dyuman Joshi
2023-3-28
If you need every alphabet presented individually, you will have to define them as strings.
Either manually define each input with double inverted commas
Course1=["A","B","C","E","F","G","I","P","Q"]; %similarly for Course2 and Course3
or use compose on the existing data -
Course1=['A','B','C','E','F','G','I','P','Q'];
Course2=['B','E','F','H','K','Q','R','S','T','U','V','Z'];
Course3=['C','E','G','H','J','K','O','Q','Z'];
Course1=compose("%s",Course1')';
Course2=compose("%s",Course2')';
Course3=compose("%s",Course3')'
Course1orCourse2 = union(Course1,Course2)
Course1andCourse2 = intersect(Course1,Course2)
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