I am trying to get the answer for the sum to infinity for a geometric series. My output should be 3/2 and a loop should be used. I've done that but it won't work. Please help

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Mpho
Mpho 2023-3-28
评论： Mpho 2023-3-28
Sequence = [1 1/3 1/9 1/27];
FirstTerm = Sequence(1);
CommonRatio = Sequence(2)/Sequence(1);
n = 0;
if (Sequence(2)/Sequence(1)) == (Sequence(end)/Sequence(end-1))
CommonRatio;
for i = 0:1:10000
n = n+1;
Sum2Infinity = FirstTerm * CommonRatio.^n;
end
end
disp(Sum2Infinity)

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采纳的回答

Torsten
Torsten 2023-3-28
编辑：Torsten 2023-3-28
Sum2Infinity = 0.0;
for i = 0:1:10000
Sum2Infinity = Sum2Infinity + FirstTerm * CommonRatio^i;
end

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