Calculate a curve out of points and the curvature radius

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Jon Bilbao 2023-4-13

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1946428-calculate-a-curve-out-of-points-and-the-curvature-radius

回答： Jon Bilbao 2023-4-13

采纳的回答： Jon Bilbao

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I have a curve with a variable curvature radius and i want to calculate a function tha defines that radius.

x and y are the coordinates of some points in the x an y axis, and with that ponts i want to calculate a curve fitting them with splines and the calculate de curvature radius of that curve.

I dont know why theres is an error in this function.

Does anyone know how to solve it?

Thanks

function [r] = rtrans2(x,y)
%UNTITLED3 Summary of this function goes here
%   Detailed explanation goes here
s=csapi(x,y);
r=((diff(s,2)).^2)/(1+diff(s,1).^2);
end

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Jon Bilbao 2023-4-13

编辑：Jon Bilbao 2023-4-13

在 MATLAB Online 中打开

The problem is solved thanks , with fnder the function worked, the function is the next:

function [r] = rtdef(x,y,Lc)
xi = 0:0.1:Lc;
pp = csapi(x, y);
yi = ppval(pp, xi);
yp = fnval(fnder(pp), xi);
ypp = fnval(fnder(pp,2), xi);
r = ((1 + yp.^2).^(3/2)) ./ abs(ypp);
end

Sam Chak 2023-4-13

@Jon Bilbao, good to see that you've found the solution. I'd advise you to move your solution in the comment to the Answer section.

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采纳的回答

Jon Bilbao 2023-4-13

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1946428-calculate-a-curve-out-of-points-and-the-curvature-radius#answer_1215333

在 MATLAB Online 中打开

Solved:

function [r] = rtdef(x,y,Lc)
xi = 0:0.1:Lc;
pp = csapi(x, y);
yi = ppval(pp, xi);
yp = fnval(fnder(pp), xi);
ypp = fnval(fnder(pp,2), xi);
r = ((1 + yp.^2).^(3/2)) ./ abs(ypp);
end