I think there are dozens of possibilities, I just thought about this particular one:
if mod(size(m,1),2)==0
m=[m;nan(1,size(m,2))];
end
m(1:2:end)=0;
if isnan(m(end,2))
m=m(1:end-1,:);
end
Please note that there must not be NaNs in the matrix. If there are NaNs, this code must be little modified. Tell me in this case.
