error in arithenco and arithdeco
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original=imread('Lena.bmp'); % Read an image Lena 512*512 to original variable
seq=mortonx(original); % convert the matrix original into a vector by morton scan order which is a fucntion i made up by myself
ta=tabulate(seq); % create a three column with the internal function ... first column is the symbol... second is the times it occured ... third is the propability
count=ta(:,2); %copy the count column into count variable from ta variable
code=arithenco(seq,count); %appply the arithmetic coding ...
new=arithdeco(code,count,262144); %apply the arithmetic decoding to restore the original image ...
isequal(seq,new); % to see if seq and new are equal ....
% ??? Error using ==> arithenco at 36
% The symbol sequence parameter must be a vector of positive finite integers.
1 个评论
vishnu
2012-2-29
can you send the or post the function which converts the image into vector by morton scanning
回答（2 个）
Wayne King
2011-10-26
0 个投票
arithenco() expects an input like [1 2 3 4].
what is seq?
1 个评论
Wayne King
2011-10-26
I mean you told us seq comes from your function mortonx, but is it a vector of positive integers?
Diyar Aldusky
2011-10-27
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1 个评论
Wayne King
2011-10-27
Diyar, it's not important just that it is a vector, what are the values in original, are they all positive integers as I asked you in my first answer.
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2011-10-26
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