How can I write y0 code in one line and still I can get this output.

Question

SAHIL SAHOO 2023-5-2

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1956559-how-can-i-write-y0-code-in-one-line-and-still-i-can-get-this-output

评论： VBBV 2023-5-3

y0= [ (1e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));

(1e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));

(1e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1)); ]

================================================

output

y0 = 0.0016

0.0079

0.6824

0.0017

0.0060

1.2281

0.0069

0.0075

-1.1515

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Answer 1

VBBV 2023-5-2

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1956559-how-can-i-write-y0-code-in-one-line-and-still-i-can-get-this-output#answer_1227494

在 MATLAB Online 中打开

y0= [ (1e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (1e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
      (1e-2)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1)); ]
y0 = 9×1
    0.0082
    0.0023
   -0.4870
    0.0071
    0.0082
    1.1632
    0.0008
    0.0039
    1.7553
y0 = [1e-2*rand(6,1);repmat((-3.14)*rand(1)+(3.14)*rand(1),3,1)]
y0 = 9×1
    0.0018
    0.0012
    0.0068
    0.0078
    0.0044
    0.0079
   -1.7388
   -1.7388
   -1.7388

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SAHIL SAHOO 2023-5-3

Here I'm having same problem that you have, the first two no.

0.0031

0.0010

0.8000

0.0083

0.0089

1.8618

0.0020

0.0010

1.6583

are less than 0.0031 but the 3rd no. is between -3.14 to 3.14,

therefore I want to modify my code in such manner that I can satisfy my given condition.

VBBV 2023-5-3

在 MATLAB Online 中打开

how is it less than 0.0031 ? take a look at the values, they are just randome values multiplied by 1e-2. if you want the first two values to higher than 0.0031, then you can use randi instead of rand

y0 = [ 0.0096
    0.0081
    0.0060
    0.0044
    0.0098
    0.0030
   -0.3596
   -0.0365
   -0.3486]
y0 = 9×1
    0.0096
    0.0081
    0.0060
    0.0044
    0.0098
    0.0030
   -0.3596
   -0.0365
   -0.3486
y0 = [1e-2*randi([0 10],6,1);[(-3.14)*rand(1)+(3.14)*rand(1)].*rand(3,1)]
y0 = 9×1
    0.0700
    0.1000
    0.0500
    0.0600
    0.0600
    0.0700
   -0.2265
   -0.4150
   -0.3119