Convert Julian Date to Calendar Days.

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I'm trying to Convert the Julian-Time header to include the Year header and output the format mm/dd/yyyy. i.e. 12/31/2022 & 01/01/2023.
The complete data for Book1.xlsx contains multiple years.
Thank you!

采纳的回答

Cris LaPierre
Cris LaPierre 2023-5-2
Perhaps a bit convoluted, but this appears to work. I haven't compared it extensively to the orginal data. Note that the display format only modifies how the data appears. The time is still there.
data = readtable('Book1.xlsx',"TextType","string");
Warning: Column headers from the file were modified to make them valid MATLAB identifiers before creating variable names for the table. The original column headers are saved in the VariableDescriptions property.
Set 'VariableNamingRule' to 'preserve' to use the original column headers as table variable names.
% your Julian_dates are surrounded by quotes. Remove them
data.Julian_Time = erase(data.Julian_Time,"'");
% use datetime to convert the combined date string to a datetime.
% DDD indicates day-of-year
data.Julian_Time = datetime(data.Year+"-"+data.Julian_Time,'InputFormat','uuuu-DDD-HH:mm:ss.SSS');
data.Julian_Time.Format = 'MM/dd/yyyy'
data = 185×4 table
Year Julian_Time Data1 Data2 ____ ___________ ______ ______ 2022 12/31/2022 36.425 21.998 2022 12/31/2022 36.725 21.998 2022 12/31/2022 36.425 21.998 2022 12/31/2022 36.425 21.998 2022 12/31/2022 36.725 21.998 2022 12/31/2022 36.725 21.998 2022 12/31/2022 36.425 21.998 2022 12/31/2022 36.425 21.998 2022 12/31/2022 36.425 21.998 2022 12/31/2022 36.725 21.998 2022 12/31/2022 36.725 21.998 2022 12/31/2022 36.425 21.998 2022 12/31/2022 36.425 21.998 2022 12/31/2022 36.725 21.998 2022 12/31/2022 36.425 21.998 2022 12/31/2022 36.425 21.998

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