keep solution from function into an array

Question

Qonitat 2023-5-8

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1960054-keep-solution-from-function-into-an-array

评论： Qonitat 2023-5-9

i want to save solution from a function into an array, there will be x & fval loop input, and i want to save all the incumbent from the previous input to find the maximums ones, can someone help me? sorry for my english

function [x,fval] = BnB(f, A, b, Aeq, beq, lb, ub)
[x,fval] = linprog(f,A,b,Aeq,beq,lb,ub); 
[incumbent] = updateincumbent(x,fval)
for i=1:length(x)
        if --- && --- && fval>=incumbent
            K = ; 
            K(i)=;
            Aeq1 = [--];
            beq1 = [--];
            Aeq2 = [--];
            beq2 = [--];
            [x1,fval1] = BnB(f, A, b, Aeq1, beq1, lb, ub);
            [x2,fval2] = BnB(f, A, b, Aeq2, beq2, lb, ub);
            
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%incumbent function file
function [incumbent] = updateincumbent(x, fval)
if mod(x,1)==0 & isempty(fval)==0
    incumbent=[fval];
else
    incumbent=[0];
%here i want to save the incumbent into an array with the previous
%incumbent then saerch the maximum ones
incumbent=max(incumbent)

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Answer 1

LeoAiE 2023-5-9

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1960054-keep-solution-from-function-into-an-array#answer_1231334

在 MATLAB Online 中打开

function [x, fval, incumbent] = BnB(f, A, b, Aeq, beq, lb, ub, incumbent)
[x, fval] = linprog(f, A, b, Aeq, beq, lb, ub); 
[incumbent] = updateincumbent(x, fval, incumbent);
for i = 1:length(x)
    if --- && --- && fval >= incumbent
        K = ; 
        K(i) = ;
        Aeq1 = [--];
        beq1 = [--];
        Aeq2 = [--];
        beq2 = [--];
        [x1, fval1, incumbent] = BnB(f, A, b, Aeq1, beq1, lb, ub, incumbent);
        [x2, fval2, incumbent] = BnB(f, A, b, Aeq2, beq2, lb, ub, incumbent);
    end
end
function [incumbent] = updateincumbent(x, fval, incumbent)
if mod(x, 1) == 0 && isempty(fval) == 0
    incumbent = [incumbent, fval];
else
    incumbent = [incumbent, 0];
end
incumbent = max(incumbent);
[x, fval, incumbent] = BnB(f, A, b, Aeq, beq, lb, ub, []);