How do I do this summation equation in MATLAB

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Brian
Brian 2023-5-11
评论： Torsten 2023-5-12
Hi! I'm a beginner MATLAB user and I'm trying to implement this summation equation in MATLAB but I'm not really sure how?
I'm used to other programming languages so I'd likely just use a nested for loop but I'm not sure if that's the best approach with MATLAB.
Equation is here:
where u is a pair and is a 128x128 matrix
My current best guess is to use nested for loops as such:
eta = zeros(1, N); % 1xN column vector to store answer
for row = 1:N %u1 is a "row"
tmp = 0;
for col = 1:N/2 % u2 is the "column" and only goes to N/2 (specified elsewhere)
tmp = tmp + abs(Y(row, col))^2;
end
eta(1, row) = tmp / N;
end

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采纳的回答

Matt J
Matt J 2023-5-11
编辑：Matt J 2023-5-11
Looks like you could simply do it in one line with,
eta=vecnorm(Y(:,1:N/2),2,2).^2/N ;
  2 个评论
Brian
Brian 2023-5-11
Is that effectively the same as the way I have it done currently? Just more succint?
Torsten
Torsten 2023-5-12
Ran in:
N = 4;
Y = rand(N) + 1i*rand(N);
eta = zeros(1, N); % 1xN column vector to store answer
for row = 1:N %u1 is a "row"
tmp = 0;
for col = 1:N/2 % u2 is the "column" and only goes to N/2 (specified elsewhere)
tmp = tmp + abs(Y(row, col))^2;
end
eta(1, row) = tmp / N;
end
eta
eta = 1×4
0.0859 0.2986 0.3841 0.3292
eta=vecnorm(Y(:,1:N/2),2,2).^2/N;
eta
eta = 4×1
0.0859 0.2986 0.3841 0.3292

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