How do I do this summation equation in MATLAB

1 次查看（过去 30 天）
Brian
Brian 2023-5-11
评论： Torsten 2023-5-12
Hi! I'm a beginner MATLAB user and I'm trying to implement this summation equation in MATLAB but I'm not really sure how?
I'm used to other programming languages so I'd likely just use a nested for loop but I'm not sure if that's the best approach with MATLAB.
Equation is here:
where u is a pair and is a 128x128 matrix
My current best guess is to use nested for loops as such:
eta = zeros(1, N); % 1xN column vector to store answer
for row = 1:N %u1 is a "row"
tmp = 0;
for col = 1:N/2 % u2 is the "column" and only goes to N/2 (specified elsewhere)
tmp = tmp + abs(Y(row, col))^2;
end
eta(1, row) = tmp / N;
end

请先登录，再回答此问题。

采纳的回答

Matt J
Matt J 2023-5-11
编辑：Matt J 2023-5-11
Looks like you could simply do it in one line with,
eta=vecnorm(Y(:,1:N/2),2,2).^2/N ;
  2 个评论
Brian
Brian 2023-5-11
Is that effectively the same as the way I have it done currently? Just more succint?
Torsten
Torsten 2023-5-12
Ran in:
N = 4;
Y = rand(N) + 1i*rand(N);
eta = zeros(1, N); % 1xN column vector to store answer
for row = 1:N %u1 is a "row"
tmp = 0;
for col = 1:N/2 % u2 is the "column" and only goes to N/2 (specified elsewhere)
tmp = tmp + abs(Y(row, col))^2;
end
eta(1, row) = tmp / N;
end
eta
eta = 1×4
0.0859 0.2986 0.3841 0.3292
eta=vecnorm(Y(:,1:N/2),2,2).^2/N;
eta
eta = 4×1
0.0859 0.2986 0.3841 0.3292

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by