How do I access structrure fields from input parser optional inputs

9 次查看(过去 30 天)
I am trying to pass in one and optionally two structures of the same type to a function using the input parser. I can access the fields of the first required structure, but I can't access the fields of the second optional structure. For the sample code below, a call of
ptest(s1)
works fine, but a call of,
ptest(s1, 's2', s2)
returns an error message of
Undefined variable "s2" or class "s2.dpri".
Error in ptest (line 22) fprintf('s2 field 1: %f\n', s2.dpri)
Here is the sample code:
function [] = ptest( s1, varargin )
%%Input Parser
p = inputParser;
p.StructExpand = false;
% Defaults for optional input
default_s2 = 'none';
addRequired(p,'s1', @(x) isstruct(x));
addParameter(p,'s2', default_s2, @(x) isstruct(x));
parse(p,s1,varargin{:});
% Check if optional parameters were specified
opt.s2 = ~any(strcmp('s2',p.UsingDefaults));
%%Actions based on s1
fprintf('s1 field 1: %f\n', s1.dpri)
fprintf('s1 field 2: %f\n', s1.dsec)
%%Actions based on s2
if opt.s2
fprintf('s2 field 1: %f\n', s2.dpri)
fprintf('s2 field 2: %f\n', s2.dsec)
end
end

采纳的回答

Mohammad Abouali
Mohammad Abouali 2015-4-5
编辑:Mohammad Abouali 2015-4-5
That's not how varargin works if you have
function ptest(s1,varargin)
....
end
then once you call it as:
ptest(s1,'s2',s2)
to access s2 within ptest you need to use varargin{2} for example you need to change the following part of your code as shown here
%%Actions based on s2
if opt.s2
%fprintf('s2 field 1: %f\n', s2.dpri)
%fprintf('s2 field 2: %f\n', s2.dsec)
fprintf('s2 field 1: %f\n', varargin{2}.dpri)
fprintf('s2 field 2: %f\n', varargin{2}.dsec)
end
alternatively you can access it using your parser object variable (p) as follow
p.Results.s2
This works if you have setup the parser object properly of course.

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 String Parsing 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by