How to take laplace transform of square(t) function
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Problem: http://imgur.com/NjI0XEF Plot for Part A: http://imgur.com/KXoMZ92 Code so far: http://pastebin.com/EJXZJi3d
I am currently on part b. I believe the problem is asking me to generate the square wave, which I do through square(t) from 0 to 30. But when I take the laplace transform I get an error.
syms s j Y;
f=square(j);
F=laplace(f,j,s)
-----------------------------------
Input arguments must be 'double'.
I can generate the wave but then I can't use the laplace transform. I've tried generating the square wave by using sin(t)/abs(sin(t)) but I don't know how to use the output of that function either.
Using this video and this pdf I believe the laplace transform is (exp(-s*pi) - 1)/(s*(exp(-s*pi) + 1) but I cannot replicate this in matlab.
What is the best way to generate this wave and obtain its laplace transform, should I just try to do the steps the same as in the video and ignore the laplace function or am I missing something?
1 个评论
RahulTandon
2015-7-7
编辑：Image Analyst
2015-7-15
do you mind asimulink solution to the problem?
回答（1 个）
Philip Caplan
2015-4-15
编辑：Philip Caplan
2015-4-15
Since this is a homework problem, I'll only give some hints. The reason you are getting the error message "Input arguments must be 'double'" is because "square" is not defined for symbolic inputs. However, from your homework question, note that "h(t) is defined on [0,10*pi]" which can be described by:
syms t
n = 10;
h = heaviside(t);
for i=1:n
h = h +2*((-1)^i)*heaviside(t -i*pi);
end
You can then call "laplace(h)" but note this is only a part of the full square wave, defined on [0,10*pi]. Hope this helps.
1 个评论
laisha
2016-9-13
If i want n equals to infinity, what changes should i make? The function gives an error
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2015-4-13
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