No API supports functions `bar` and `legend` in multi-figure

Question

Yihang Xu 2023-6-21

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1986149-no-api-supports-functions-bar-and-legend-in-multi-figure

评论： Yihang Xu 2023-6-21

clear, close all
x1 = rand(1,18);
x2 = rand(1,18);
x3 = rand(1,18);
x4 = rand(1,18);
myLegends = {"A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R"};
colors = rand(18,3);

t = tiledlayout('flow', 'TileSpacing', 'compact');

nexttile

b1 = bar(x1);

b1.FaceColor = 'flat';

for i = 1:length(colors)

b1.CData(i,:) = colors(i,:);

end

set(gca,'XTickLabel',[]);

nexttile

b2 = bar(x2);

b2.FaceColor = 'flat';

for i = 1:length(colors)

b2.CData(i,:) = colors(i,:);

end

set(gca,'XTickLabel',[]);

nexttile

b3 = bar(x3);

b3.FaceColor = 'flat';

for i = 1:length(colors)

b3.CData(i,:) = colors(i,:);

end

set(gca,'XTickLabel',[]);

nexttile

b4 = bar(x4);

b4.FaceColor = 'flat';

for i = 1:length(colors)

b4.CData(i,:) = colors(i,:);

end

set(gca,'XTickLabel',[]);

lgd = legend(myLegends);

Warning: Ignoring extra legend entries.

lgd.Layout.Tile = 'east';

i'd like to create a legend on the right, and the legend should contains 18 labels corresponding to the colors. i tried my best but failed.

The main reason is that the bar function does not support individual bars forming a group, resulting in the legend function not being able to recognize bars of different colors.

The second reason lies in that `legend` function does not support custom creation, that is, creating with preset colors and labels from the scratch.

Call on developers to make improvements.

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Answer 1

Benjamin Kraus 2023-6-21

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https://ww2.mathworks.cn/matlabcentral/answers/1986149-no-api-supports-functions-bar-and-legend-in-multi-figure#answer_1259984

编辑：Benjamin Kraus 2023-6-21

在 MATLAB Online 中打开

You can only have one legend entry per bar object, and each of your calls to the bar command creates only one bar object.

You have two options:

Option 1: Multiple calls to bar

@Vishnu is on the right track with the first option (which is to call the bar command multiple times), but left out the x-data when calling the bar command:

x1 = rand(1,18);

x2 = rand(1,18);

x3 = rand(1,18);

x4 = rand(1,18);

myLegends = {"A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R"};

colors = rand(18,3);

t = tiledlayout('flow', 'TileSpacing', 'compact');

nexttile

b1 = bar(1, x1(1),'FaceColor',colors(1,:));

hold on

for i = 2:height(colors)

b1(i) = bar(i, x1(i), 'FaceColor',colors(i,:));

end

xticks auto

nexttile

b2 = bar(1, x2(1),'FaceColor',colors(1,:));

hold on

for i = 2:height(colors)

b2(i) = bar(i, x2(i), 'FaceColor',colors(i,:));

end

xticks auto

nexttile

b3 = bar(1, x3(1),'FaceColor',colors(1,:));

hold on

for i = 2:height(colors)

b3(i) = bar(i, x3(i), 'FaceColor',colors(i,:));

end

xticks auto

nexttile

b4 = bar(1, x4(1),'FaceColor',colors(1,:));

hold on

for i = 2:height(colors)

b4(i) = bar(i, x4(i), 'FaceColor',colors(i,:));

end

xticks auto

lgd = legend(b4, myLegends);

lgd.Layout.Tile = 'east';

Option 2: Use a diagonal matrix

This version produces the same results as the above, but it cheats a little and uses a diagonal matrix to do it.

figure

t = tiledlayout('flow', 'TileSpacing', 'compact');

nexttile

x1Mat = diag(x1);

b1 = bar(x1Mat,'stacked');

for i = 1:numel(b1)

b1(i).FaceColor = colors(i,:);

end

set(gca,'XTickLabel',[]);

nexttile

x2Mat = diag(x2);

b2 = bar(x2Mat,'stacked');

for i = 1:numel(b2)

b2(i).FaceColor = colors(i,:);

end

set(gca,'XTickLabel',[]);

nexttile

x3Mat = diag(x3);

b3 = bar(x1Mat,'stacked');

for i = 1:numel(b3)

b3(i).FaceColor = colors(i,:);

end

set(gca,'XTickLabel',[]);

nexttile

x4Mat = diag(x4);

b4 = bar(x4Mat,'stacked');

for i = 1:numel(b4)

b4(i).FaceColor = colors(i,:);

end

set(gca,'XTickLabel',[]);

lgd = legend(b4, myLegends);

lgd.Layout.Tile = 'east';

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Yihang Xu 2023-6-21

Thanks a lot. Option 1 works well.

i have thought about the option 2,but did not make this trade-off.

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Answer 2

Vishnu 2023-6-21

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链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1986149-no-api-supports-functions-bar-and-legend-in-multi-figure#answer_1259894

在 MATLAB Online 中打开

Hi Yihang,

It looks like you are trying to create a bar plot with individual colors for each bar and add a legend to it. Unfortunately, the legend function won't be able to recognize bars with different colors when they are created separately using the bar function.

However, you can create the legend manually using a loop to plot each color with its corresponding label. Here is the code ,

clear, close all

x1 = rand(1,18);

x2 = rand(1,18);

x3 = rand(1,18);

x4 = rand(1,18);

myLegends = {"A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R"};

colors = rand(18,3);

t = tiledlayout('flow', 'TileSpacing', 'compact');

nexttile

b1 = bar(x1,'FaceColor',colors(1,:));

set(gca,'XTickLabel',[]);

hold on;

for i = 2:length(colors)

tempbar = bar(x1(i),'FaceColor',colors(i,:));

end

nexttile

b2 = bar(x2,'FaceColor',colors(1,:));

set(gca,'XTickLabel',[]);

hold on;

for i = 2:length(colors)

tempbar = bar(x2(i),'FaceColor',colors(i,:));

end

nexttile

b3 = bar(x3,'FaceColor',colors(1,:));

set(gca,'XTickLabel',[]);

hold on;

for i = 2:length(colors)

tempbar = bar(x3(i),'FaceColor',colors(i,:));

end

nexttile

b4 = bar(x4,'FaceColor',colors(1,:));

set(gca,'XTickLabel',[]);

hold on;

for i = 2:length(colors)

tempbar = bar(x4(i),'FaceColor',colors(i,:));

end

lgd = legend(myLegends,'Location','east');

lgd.String = {}; % clear existing legend strings

for i = 1:length(myLegends)

l(i) = line(nan, nan, 'LineWidth', 10, 'Color', colors(i,:));

lgd.String{i} = myLegends{i};

end

% you can move the lengend by dragging it, after running in MATLAB.

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Yihang Xu 2023-6-21

在 MATLAB Online 中打开

The results does not meet my expectations. However, i am inspired by it to write this code, just modify a number from 1 to 2

clear, close all

x1 = rand(1,18);

x2 = rand(1,18);

x3 = rand(1,18);

x4 = rand(1,18);

myLegends = {"A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R"};

colors = rand(18,3);

t = tiledlayout('flow', 'TileSpacing', 'compact');

nexttile

b1 = bar(x1);

b1.FaceColor = 'flat';

for i = 1:length(colors)

b1.CData(i,:) = colors(i,:);

end

set(gca,'XTickLabel',[]);

nexttile

b2 = bar(x2);

b2.FaceColor = 'flat';

for i = 1:length(colors)

b2.CData(i,:) = colors(i,:);

end

set(gca,'XTickLabel',[]);

nexttile

b3 = bar(x3);

b3.FaceColor = 'flat';

for i = 1:length(colors)

b3.CData(i,:) = colors(i,:);

end

set(gca,'XTickLabel',[]);

nexttile

b4 = bar(x4);

b4.FaceColor = 'flat';

for i = 1:length(colors)

b4.CData(i,:) = colors(i,:);

end

set(gca,'XTickLabel',[]);

lgd = legend(myLegends);

Warning: Ignoring extra legend entries.

lgd.Layout.Tile = 'east';

lgd.String = {}; % clear existing legend strings

for i = 2:length(myLegends)

l(i) = line(nan, nan, 'LineWidth', 10, 'Color', colors(i,:));

lgd.String{i} = myLegends{i};

end

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No API supports functions `bar` and `legend` in multi-figure

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No API supports functions `bar` and `legend` in multi-figure

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