how to clip a domain data from global data?

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I am trying to clip South Asia domain (19.25°E-116.25°E,-15.75°S-45.75°N) from a global dataset with 0.5 degree resolution.
Here is the code i am using:
global_data = load('global_data.mat');
% Define the latitude and longitude boundaries
lat_start = -15.75;
lat_end = 45.75;
lon_start = 19.25;
lon_end = 116.25;
% Define the resolution
resolution = 0.5;
% Calculate the indices for cropping
lat_indices = floor((lat_start + 90) / resolution) + 1 : floor((lat_end + 90) / resolution) + 1;
lon_indices = floor((lon_start + 180) / resolution) + 1 : floor((lon_end + 180) / resolution) + 1;
% Crop the global data
cropped_data = global_data(lat_indices, lon_indices, :);
% Display the size of the cropped data
disp(size(cropped_data));
Can someone help me with this?
Thank you.

回答(2 个)

Sulaymon Eshkabilov
Here are two ways to get it with two small corrections in your code:
Way - 1. Just use load() without variable name assigning, because the variable name is the same:
load('global_data.mat');
% Define the latitude and longitude boundaries
lat_start = -15.75;
lat_end = 45.75;
lon_start = 19.25;
lon_end = 116.25;
% Define the resolution
resolution = 0.5;
% Calculate the indices for cropping
lat_indices = floor((lat_start + 90) / resolution) + 1 : floor((lat_end + 90) / resolution) + 1;
lon_indices = floor((lon_start + 180) / resolution) + 1 : floor((lon_end + 180) / resolution) + 1;
% Crop the global data
cropped_data = global_data(lat_indices, lon_indices, :);
% Display the size of the cropped data
disp(size(cropped_data));
124 195 12
Way - 2. Read data from Stucture variable, e.g.: global_data.global_data
global_data = load('global_data.mat');
global_data = load('global_data.mat');
% Define the latitude and longitude boundaries
lat_start = -15.75;
lat_end = 45.75;
lon_start = 19.25;
lon_end = 116.25;
% Define the resolution
resolution = 0.5;
% Calculate the indices for cropping
lat_indices = floor((lat_start + 90) / resolution) + 1 : floor((lat_end + 90) / resolution) + 1;
lon_indices = floor((lon_start + 180) / resolution) + 1 : floor((lon_end + 180) / resolution) + 1;
% Crop the global data
cropped_data = global_data.global_data(lat_indices, lon_indices, :);
% Display the size of the cropped data
disp(size(cropped_data));
124 195 12
  1 个评论
Vidushi Koliyan
Vidushi Koliyan 2023-6-28
编辑:Vidushi Koliyan 2023-6-28
Actually, i need to compare two data. I am attaching two figures. One is data i want to compare with (ori_im) and the clipped figure(clip_im). Now, extent of the domain is same that i am giving as input in my code. But it is not extracting correct domain. Can you suggest what could be the possible reason?

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Sulaymon Eshkabilov
If understood your question correctly, what you want is to display your cropped data, right?
If so, here is how it can be done:
load('global_data.mat');
% Define the latitude and longitude boundaries
lat_start = -15.75;
lat_end = 45.75;
lon_start = 19.25;
lon_end = 116.25;
% Define the resolution
resolution = 0.5;
% Calculate the indices for cropping
lat_indices = floor((lat_start + 90) / resolution) + 1 : floor((lat_end + 90) / resolution) + 1;
lon_indices = floor((lon_start + 180) / resolution) + 1 : floor((lon_end + 180) / resolution) + 1;
% Crop the global data
cropped_data = global_data(lat_indices, lon_indices, :);
% Display the size of the cropped data
disp(size(cropped_data));
124 195 12
figure
imagesc(cropped_data(:,:,1)) % Cropped data set
figure
imagesc(global_data(:,:,1)) % Whole data set
In order to create the two image as you mentioned, you need to specify the corodinates (indices) as in this cropped one.
  1 个评论
Vidushi Koliyan
Vidushi Koliyan 2023-6-28
No. Actually the figure with "ori_im" name is the domain data that i need. And the coordinates are "South Asia domain (19.25°E-116.25°E,-15.75°S-45.75°N". But with these coordinates, i am getting the result (as you showed in your cropped_data figure) which is not correct domain data. So basically it is clipping a wrong domain.
Am I clear with my question? Sorry if i am not able to explain it correctly.

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