Euler's identity with angle in degrees

Question

Ali Kiral 2023-6-30

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https://ww2.mathworks.cn/matlabcentral/answers/1990228-euler-s-identity-with-angle-in-degrees

评论： Ali Kiral 2023-6-30

How can I get MATLAB to accept a in degress in exp(aj) to return a complex number where j^2=-1? By default the software takes a in radians.

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Answer 1

Torsten 2023-6-30

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https://ww2.mathworks.cn/matlabcentral/answers/1990228-euler-s-identity-with-angle-in-degrees#answer_1265298

编辑：Torsten 2023-6-30

在 MATLAB Online 中打开

a = 30;
exp(deg2rad(a)*1i)
ans = 0.8660 + 0.5000i
exp(a*pi/180*1i)
ans = 0.8660 + 0.5000i

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Answer 2

Joe Vinciguerra 2023-6-30

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https://ww2.mathworks.cn/matlabcentral/answers/1990228-euler-s-identity-with-angle-in-degrees#answer_1265318

编辑：Joe Vinciguerra 2023-6-30

在 MATLAB Online 中打开

[EDIT: oops. converted in the wrong direction.]

deg2rad will convert degrees to radians (https://www.mathworks.com/help/matlab/ref/deg2rad.html).

So you'll do something like this:

j = sqrt(-1);
a = 180;
exp(deg2rad(a)*j)
ans = -1.0000 + 0.0000i

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Answer 3

Paul 2023-6-30

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https://ww2.mathworks.cn/matlabcentral/answers/1990228-euler-s-identity-with-angle-in-degrees#answer_1265443

在 MATLAB Online 中打开

If the input is given in degrees, consider writing your own function using cosd and sind for accurate results at the 90 deg intervals

e = @(x) cosd(x) + 1i*sind(x);
d = [90 180 270];
format long e
e(d)
ans = 
      0.000000000000000e+00 + 1.000000000000000e+00i     -1.000000000000000e+00 + 0.000000000000000e+00i      0.000000000000000e+00 - 1.000000000000000e+00i
exp(d*pi/180*1i)
ans = 
      6.123233995736766e-17 + 1.000000000000000e+00i     -1.000000000000000e+00 + 1.224646799147353e-16i     -1.836970198721030e-16 - 1.000000000000000e+00i