How can I convert an Array with row values to a binary Matrix?
2 次查看(过去 30 天)
显示 更早的评论
Hi,
I have an array A containing natural numbers. The indices of the array represent the current column and the numbers itself represent the rows of a matrix M. Now I want to set the matrix at one for the corresponding values in the array.
Like the following code
A = [2 3 3 4 5 4 3];
M = zeros(length(A));
for i= 1:length(A)
M(A(i),i) = 1;
end
M
I know that using loops in Matlab can be very slow and I want a faster way of computing this, since the array in my project has a length of 60000. Is there a way to run compute this faster?
0 个评论
采纳的回答
Cris LaPierre
2023-6-30
A = [2 3 3 4 5 4 3];
M = zeros(length(A));
Col = 1:length(A);
ind = sub2ind(size(M),A,Col);
M(ind) = 1
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Logical 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!