I want to extract rows from my matrix that have a specific value in the second column.
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I want to take all of the rows from a matrix that have a 1 in the second column and create a new matrix with these rows.
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Kavita Guddad
2023-7-5
x=[1 2 3 5;2 3 4 5;2 1 3 4;2 1 3 2 ];
y=[];
for i=1:size(x,1)
if (x(i,2)==1)
y=[y;x(i,:)];
end
end
disp(x)
disp(y)
采纳的回答
Kavita Guddad
2023-7-5
Hope this code does your job.
x=[1 2 3 5;2 3 4 5;2 1 3 4;2 1 3 2 ];
y=[];
for i=1:size(x,1)
if (x(i,2)==1)
y=[y;x(i,:)];
end
end
disp(x)
disp(y)
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更多回答(1 个)
Abhas
2023-7-5
编辑:Abhas
2023-7-5
Hi Philip,
We can use logical indexing to select only the rows where the second column has a value of 1. The below code can solve your query:
% Sample input matrix
inputMatrix = [2, 1, 3;
4, 1, 6;
7, 0, 9;
1, 1, 2;
8, 1, 5];
% Find rows with a 1 in the second column
rowsWithOne = inputMatrix(inputMatrix(:, 2) == 1, :);
Hope this helps!
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