Mean of cell array with non-uniform cell array size size

Question

Konvictus177 2023-8-16

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2009137-mean-of-cell-array-with-non-uniform-cell-array-size-size

评论： Konvictus177 2023-8-16

Hi,

I have a cell array that stores a vector in each cell. The vector in each cell usually has 5 elements but somtimes it does have more or less than 5 elements.

I want to take the mean per vector row for each cell row but only do this where the vector length is 5. I dont want to use the vectors that have more or less than 5 elements.

Thanks.

This is how far I got:

slots = 16;
for i=1:slots
    mean_height{i} = mean([heights{i,1:profiles(i)}],2)
end

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Answer 1

Florian Bidaud 2023-8-16

1
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2009137-mean-of-cell-array-with-non-uniform-cell-array-size-size#answer_1288312

编辑：Florian Bidaud 2023-8-16

在 MATLAB Online 中打开

Something like this should do the job:

slots = 16;
height_row = [];
for i=1:slots
    for j = 1:profiles(i)
        if length(heights{i,j})==5
            height_row = [height_row heights{i,j}'];
        end
    end
    mean_height{i} = mean(height_row,2);
end

I don't really like the double loop, there might be something to do with logical indexing but I can't find my way around it.

Update:

Do this instead :

slots = 16;
for i=1:slots
    height_row = heights(i,1:profiles(i));
    height_row = height_row(cellfun('length',height_row)==5);
    mean_height{i} = mean([height_row{:}],2);
end

though I feel like you want to have the following in the end instead (depending on what you want to do):

mean_height{i} = mean(mean([height_row{:}]))

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Konvictus177 2023-8-16

在 MATLAB Online 中打开

This is exactly what I want. Thank you very much!

slots = 16;
for i=1:slots
    height_row = heights(i,1:profiles(i));
    height_row = height_row(cellfun('length',height_row)==5);
    mean_height{i} = mean([height_row{:}],2);
end