Transform double to char with one or two decimal places
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I have a series of numbers:
n_A = 3.15;
n_B = 3.7;
I have to transform them into char considering 1 or 2 decimal digits based on the starting number, i.e. like this:
n_A = 3.15;
A = sprintf('%.2f',n_A);
n_B = 3.7;
B = sprintf('%.1f',n_B);
My question is how can I apply this:
sprintf('%.2f',#);
or this:
sprintf('%.1f',#);
knowing that the number has one or two digits after the decimal point?
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回答(1 个)
Stephen23
2023-9-11
编辑:Stephen23
2023-9-11
You could use another format, e.g.:
fprintf('%.3g\n',[3.15,3.7])
2 个评论
Walter Roberson
2023-9-11
n_A = 3.15;
fprintf('%g\n', n_A);
n_B = 3.70;
fprintf('%g\n', n_B)
format long g
n_A
n_B
另请参阅
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