Split increasing vector into n unqueal parts based on multiples of n

Question

Konvictus177 2023-9-18

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2022457-split-increasing-vector-into-n-unqueal-parts-based-on-multiples-of-n

回答： Stephen23 2023-9-18

Denc.mat

Hi,
I have a vector which consists of increasing numbers.
I want to split the vector into 54 parts based on multiples of 2030. So first vector should contain all numbers from 0 until 2030. Second vector should contain all numbers from 2030 and up until 2*2030 (4060), third vector everything from 4060 up until 3*2030 (6090), etc.
Vector is attached.
Thanks.

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Dyuman Joshi 2023-9-18

在 MATLAB Online 中打开

Denc.mat

load('Denc.mat')
m=max(Denc)
m = 115279
m/2030
ans = 56.7877

You want to ignore the 55th, 56th and the 57th parts?

Also, just to confirm, you want to include the boundary values on both sides?

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Answer 1

Stephen23 2023-9-18

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/2022457-split-increasing-vector-into-n-unqueal-parts-based-on-multiples-of-n#answer_1312477

在 MATLAB Online 中打开

Denc.mat

S = load('Denc.mat');
D = S.Denc
D = 5660×1
     0
     0
     0
     0
     0
     0
     0
     0
     0
     0
B = 0:2300:2300+max(D)
B = 1×52
           0        2300        4600        6900        9200       11500       13800       16100       18400       20700       23000       25300       27600       29900       32200       34500       36800       39100       41400       43700       46000       48300       50600       52900       55200       57500       59800       62100       64400       66700
X = discretize(D,B);
C = accumarray(X,D,[],@(a){a})
C = 51×1 cell array
    {1116×1 double}
    {  60×1 double}
    {  51×1 double}
    {  51×1 double}
    {  60×1 double}
    {  58×1 double}
    {  43×1 double}
    {  36×1 double}
    {  32×1 double}
    {  30×1 double}
    {  30×1 double}
    {  30×1 double}
    {  32×1 double}
    {  35×1 double}
    {  39×1 double}
    {  41×1 double}